Windows 的 Python 服务有几个问题

Question

我已经检查了至少几十个与我类似的案例，但仍然没有提出解决方案，我希望有人能解释一下，这里一定有我遗漏的东西。

我正在使用 Python3.6 来创建一个 Windows 服务，如果它没有运行，该服务必须运行一个 .exe 文件。这是.py：

import win32service
import win32serviceutil
import win32api
import win32con
import win32event
import win32evtlogutil
import psutil
import subprocess
import os, sys, string, time
import servicemanager


class SLAAgent (win32serviceutil.ServiceFramework):
    _svc_name_ = "SLAAgent"
    _svc_display_name_ = "SLAAgent"

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
        socket.setdefaulttimeout(60)
        self.isAlive = True

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)
        self.isAlive = False

    def SvcDoRun(self):
        self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
        self.ReportServiceStatus(win32service.SERVICE_RUNNING)
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,servicemanager.PYS_SERVICE_STARTED,(self._svc_name_, ''))
        self._logger.info("Service Is Starting")
        main(self)

    def main(self):
        while self.isAlive:
            rc = win32event.WaitForSingleObject(self.hWaitStop, self.timeout)
            # Check to see if self.hWaitStop happened
            if rc == win32event.WAIT_OBJECT_0:
                servicemanager.LogInfoMsg("SLAAService has stopped")  #For Event Log
                break
            else:
                try:
                    s = subprocess.check_output('tasklist', shell=True)
                    if "SLA_Client.exe" in s:
                        pass
                    else:
                        pass
                        #execfile("SLA_Client.exe") #Execute the script
                except:
                    pass

if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(SLAAgent)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(SLAAgent)

我已经安装了 pywin32 包，将它们添加到 PATH 因为它在几个解决方案中被建议，并且还将 .dll 从 pywin32_system32 复制到 win32

环境变量

事件查看器错误

事件查看器每次运行时都会打印此错误，无论是 python service.py 还是 python service.py start，控制台也会打印：

python SLA_Agent.py
Traceback (most recent call last):
  File "SLA_Agent.py", line 56, in <module>
    servicemanager.StartServiceCtrlDispatcher()
pywintypes.error: (1063, 'StartServiceCtrlDispatcher', 'The service process 
could not connect to the service controller.')

当尝试从服务工具启动服务时，这是弹出的错误。我也看到了另一个错误，关于服务没有及时响应。

我试过用 pyinstaller 和 nuitka 编译它，错误是一样的。我不确定如何继续，我已经更改了代码以适合我使用 google 和 SO 找到的示例和解决方案，并且对方法和原因知之甚少。

如果有人以前遇到过这些问题，我非常感谢您的意见，到目前为止，其他答案对我没有帮助。

后期编辑：修复了代码缩进

Answer 1

这最终对我有用，除了代码中的差异之外，我并没有真正做任何特别的事情，经过几次尝试后，我可以使用 pyinstaller 进行编译并且service.exe install没有问题地运行。有一些人们可能不需要的额外日志记录行，但它们在调试和测试时派上用场。

非常感谢留下评论的每个人，他们非常有帮助，没有你就做不到 <3

import win32service, win32serviceutil, win32api, win32con, win32event, win32evtlogutil
import psutil
import subprocess
import os, sys, string, time, socket, signal
import servicemanager

class Service (win32serviceutil.ServiceFramework):
    _svc_name_ = "Service"
    _svc_display_name_ = "Service"

    def __init__(self,args):
        win32serviceutil.ServiceFramework.__init__(self, *args)
        self.log('Service Initialized.')
        self.stop_event = win32event.CreateEvent(None, 0, 0, None)
        socket.setdefaulttimeout(60)


    def log(self, msg):
        servicemanager.LogInfoMsg(str(msg))

    def sleep(self, sec):
        win32api.Sleep(sec*1000, True)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        self.stop()
        self.log('Service has stopped.')
        win32event.SetEvent(self.stop_event)
        self.ReportServiceStatus(win32service.SERVICE_STOPPED)

    def SvcDoRun(self):
        self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
        try:
            self.ReportServiceStatus(win32service.SERVICE_RUNNING)
            self.log('Service is starting.')
            self.main()
            win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
            servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,servicemanager.PYS_SERVICE_STARTED,(self._svc_name_, ''))
        except Exception as e:
            s = str(e);
            self.log('Exception :'+s)
            self.SvcStop()

    def stop(self):
        self.runflag=False
        try:
            #logic
        except Exception as e:
            self.log(str(e))

    def main(self):
        self.runflag=True
        while self.runflag:
            rc = win32event.WaitForSingleObject(self.stop_event, 24*60*60)
            # Check to see if self.hWaitStop happened
            if rc == win32event.WAIT_OBJECT_0:
                self.log("Service has stopped")
                break
            else:
                try:
                    #logic
                except Exception as e:
                    self.log(str(e))

if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(Service)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(Service)