带有last_insert_id()的Mysql mulitple row insert-select语句

Question

好.所以缺点是,我试图做一个INSERT SELECT,例如:

START TRANSACTION;  
INSERT INTO dbNEW.entity (commonName, surname)  
SELECT namefirst, namelast  
FROM dbOLD.user;  
SET @key = LAST_INSERT_ID();  
INSERT INTO dbNEW.user (userID, entityID, other)  
SELECT user_id, @key, other  
FROM dbOLD.user;  
COMMIT;

当然@key不会从每个插入返回每个后续的LAST_INSERT_ID(),而只返回最后一个插入的ID.

基本上,我将旧的USER表拆分为ENTITY和USER,如:

 dbOLD.user
 +-------------+---------------------+------+-----+------------+----------------+
 | Field       | Type                | Null | Key | Default    | Extra          |
 +-------------+---------------------+------+-----+------------+----------------+
 | user_id     | int(10) unsigned    | NO   | PRI | NULL       | auto_increment |
 | namefirst   | varchar(20)         | NO   |     |            |                |
 | namelast    | varchar(20)         | NO   |     |            |                |
 | other       | varchar(10)         | NO   |     |            |                |
 +-------------+---------------------+------+-----+------------+----------------+


 dbNEW.user
 +-------------+---------------------+------+-----+------------+----------------+
 | Field       | Type                | Null | Key | Default    | Extra          |
 +-------------+---------------------+------+-----+------------+----------------+
 | userID      | int(10) unsigned    | NO   | PRI | NULL       | auto_increment |
 | entityID    | int(10) unsigned    | NO   | MUL | 0          |                |
 | other       | varchar(10)         | NO   |     |            |                |
 +-------------+---------------------+------+-----+------------+----------------+


 dbNEW.entity
 +--------------+---------------------+------+-----+------------+----------------+
 | Field        | Type                | Null | Key | Default    | Extra          |
 +--------------+---------------------+------+-----+------------+----------------+
 | entityID     | int(10) unsigned    | NO   | PRI | NULL       | auto_increment |
 | commonName   | varchar(20)         | NO   |     |            |                |
 | surname      | varchar(20)         | NO   |     |            |                |
 +--------------+---------------------+------+-----+------------+----------------+

我为什么要这样做？基本上,我有一个"STORE"实体,它将具有"USERS"共有的字段,例如地址和电话号码.因此,任何"ENTITY"可能没有多个地址(运输,计费,邮寄),也没有多个电话号码(传真,主要,计费,手机,家庭)可能有其他方法可以实现这一点,但这是我的解决方案结束了.

来自旧数据库的STORE和USERS需要保留旧的PK并获得额外的ENTITY fk.如何在不进行转储和手动编辑的情况下执行此操作？

Answer 1

对于最后一个查询,请使用此选项

INSERT INTO dbNEW.`user` (userID, entityID, other)  
SELECT user_id, entityID, other
FROM
(
    SELECT user_id, @key + @rn entityID, other, @rn := @rn + 1
    FROM (select @rn:=0) x, dbOLD.`user`
    order by user_id
) y;

MySQL中的LAST_INSERT_ID()是批处理中创建的第一个ID,与SQL Server中的SCOPE_IDENTITY()不同,后者是最后一个ID.因为它是第一行,所以我们使用变量@rn递增每一行,从addition=0第一行开始.