Kla*_*aus 5 gcc user-defined-literals c++-chrono
我想使用std::chrono::duration
文字,例如10s
表示“10 秒”,如下所示:
std::chrono::duration<uint64_t, std::milli> millisecs = 10s;
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但是,我收到此错误:
Run Code Online (Sandbox Code Playgroud)main.cpp:20:17: error: unable to find numeric literal operator 'operator""s' millisecs = 20s; main.cpp:22:17: note: use -std=gnu++11 or -fext-numeric-literals to enable more built-in suffixes
我已经添加-fext-numeric-literals
到我的 gcc 编译命令中:
std::chrono::duration<uint64_t, std::milli> millisecs = 10s;
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我究竟做错了什么?