Guy*_*kes -1 c++ initialization vector
有人可以向我解释为什么Graph构造函数中的verticies.size()等于'4'但是在addEdge中再次调用verticies.size()等于0?程序在verticies [fromVertex] .addEdge(toVertex)崩溃,因为verticies的大小为0.
我确信这是我应该知道的,但我不会在哪里出错.
class Vertex {
public:
int value;
vector<int> adj;
bool isVisited = false;
Vertex(int _value)
{
value = _value;
}
void addEdge(int destination)
{
adj.push_back(destination);
}
};
class Graph
{
public:
int vertexCount; // No. of vertices
vector<Vertex> verticies;
Graph(int _vertexCount)
{
this->vertexCount = _vertexCount;
vector<Vertex> verticies;
for (size_t i = 0; i < _vertexCount; i++)
{
Vertex v = Vertex(i);
verticies.push_back(v);
}
cout << "verticies count " << verticies.size() << endl;
}
void addEdge(int fromVertex, int toVertex)
{
cout << "verticies count in addEdge: " << verticies.size() << endl;
verticies[fromVertex].addEdge(toVertex);
}
void findPath(int fromVertex, int toVertex, vector<int> pathSoFar)
{
pathSoFar.push_back(fromVertex);
if (fromVertex == toVertex)
{
for (int i = 0; i < pathSoFar.size(); i++)
{
cout << pathSoFar.at(i) << " ";
}
cout << endl;
return;
}
else
{
for (size_t i = 0; i < verticies[fromVertex].adj.size(); i++)
{
int nextToVisit = verticies[fromVertex].adj.at(i);
if (verticies[nextToVisit].isVisited == false)
{
findPath(nextToVisit, toVertex, pathSoFar);
}
}
}
}
};
int main()
{
// Create a graph given in the above diagram
Graph g(4);
g.addEdge(0, 1);
g.addEdge(0, 2);
g.addEdge(1, 2);
g.addEdge(2, 0);
g.addEdge(2, 3);
g.addEdge(3, 3);
vector<int> path;
g.findPath(2, 1, path);
return 0;
}
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有人可以向我解释为什么Graph构造函数中的verticies.size()等于'4'但是在addEdge中再次调用verticies.size()等于0?
这是因为那些是两个不同的对象.这里
Graph(int _vertexCount)
{
this->vertexCount = _vertexCount;
vector<Vertex> verticies;
// ....
}
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您正在创建一个名为verticies阴影成员变量的局部向量.简单地删除该行应该没问题.我的意思是你已经宣布成员,不需要两次;).
不过,我建议你在填充数据之前调整矢量大小,或者至少保留你需要的容量.
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