Kotlin 替换字符串中的多个单词

Question

如何使用 Kotlin 中的其他内容替换字符串的许多部分 .replace()

比如我们只需要替换一个词就可以做到

fun main(args: Array<String>) {

    var w_text = "welcome his name is John"

    println("${w_text.replace("his","here")}")
}

结果将是“欢迎来到这里，名字是约翰”。

最后我们需要的结果是“欢迎这里的名字是 alles”

通过将他的to here和john替换为alles使用 .replace()

Answer 1

对于那些有兴趣替换文本中的值映射的人：

private fun replaceText(text: String, keys: Map<String, String>): String =
    val replaced = map.entries.fold(text) { acc, (key, value) -> acc.replace(key, value) }

Answer 2

您可以使用多个连续调用来做到这一点replace()：

w_text.replace("his", "here").replace("john", "alles")

Answer 3

您可以编写一个重载扩展String::replace：

fun String.replace(vararg replacements: Pair<String, String>): String {
    var result = this
    replacements.forEach { (l, r) -> result = result.replace(l, r) }
    return result
}


fun main(args: Array<String>) {
    val sentence = "welcome his name is John"
    sentence.replace("his" to "here", "John" to "alles")
}

Answer 4

这是单行：

fun String.replace(vararg pairs: Pair<String, String>): String =
    pairs.fold(this) { acc, (old, new) -> acc.replace(old, new, ignoreCase = true) }

测试：

@Test fun rep() {

    val input = "welcome his name is John"

    val output = input.replace("his" to "her", "john" to "alles")

    println(output)

    output shouldBeEqualTo "welcome her name is alles"

}

Answer 5

如果您有许多替换规则，则创建它们的映射并replace在循环中调用该方法：

val map = mapOf("his" to "here", "john" to "alles", ...)
val sentence = "welcome his name is John"
var result = sentence
map.forEach { t, u -> result = result.replace(t, u) }
println(result)