登录控制器中覆盖的已通过身份验证的方法不起作用

Question

我正在尝试覆盖登录控制器中的经过身份验证的方法，但是不知何故它无法正常工作。我只是尝试简单地dd（）; 但仍然不起作用。

下面是我的功能代码：

public function authenticated(Request $request, $user)
{
    dd("hi");
}

我实际上希望做的如下，但是为了简单起见，我有dd（）; 在功能上。

public function authenticated(Request $request, $user)
{
    if (!$user->verified) {
        auth()->logout();
        return back()->with('warning', 'You need to confirm your account. We have sent you an activation code, please check your email.');
    }
    return redirect()->intended($this->redirectPath());
}

整个控制器：

<?php
namespace App\Http\Controllers\Auth;
use App\Http\Controllers\Controller;
use Illuminate\Foundation\Auth\AuthenticatesUsers;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\DB;
use Illuminate\Support\Facades\Auth;
use App\Mail\WelcomeMail;
use Illuminate\Support\Facades\Mail;

class LoginController extends Controller
{
/*
|--------------------------------------------------------------------------
| Login Controller
|--------------------------------------------------------------------------
|
| This controller handles authenticating users for the application and
| redirecting them to your home screen. The controller uses a trait
| to conveniently provide its functionality to your applications.
|
*/

use AuthenticatesUsers;

/**
 * Where to redirect users after login.
 *
 * @var string
 */

protected $redirectTo = '/home';

/**
 * Create a new controller instance.
 *
 * @return void
 */
public function __construct()
{
    $this->middleware('guest')->except('logout');
}

public function login(Request $request)
{
    if (Auth::attempt(['email' => $request->email, 'password' => $request->password, 'isActive' => '1']))
    {
        return view('homepage');
    }
    else
    {
        return $this->sendFailedLoginResponse($request, 'auth.failed_status');
    }
}


protected function authenticated(Request $request, $user)
{
    dd("HI");
  // auth()->logout();
  return back()->with('warning', 'You need to confirm your account. We have sent you an activation code, please check your email.');

// if(!$user->verified)
// {
//   auth()->logout();
//   // Auth::logout();
//   // \Auth::guard('web')->logout();
//   // added logout here
//   return back()->with('warning', 'You need to confirm your account. We have sent you an activation code, please check your email.');
// }
// return redirect()->intended($this->redirectPath());
 }
}

请忽略控制器中经过身份验证的函数中的多余注释代码。

Answer 1

那是因为您要覆盖登录功能，因此永远不会调用经过身份验证的功能。

如果您看一下特征：

public function login(Request $request)
{
    $this->validateLogin($request);

    // If the class is using the ThrottlesLogins trait, we can automatically throttle
    // the login attempts for this application. We'll key this by the username and
    // the IP address of the client making these requests into this application.
    if ($this->hasTooManyLoginAttempts($request)) {
        $this->fireLockoutEvent($request);

        return $this->sendLockoutResponse($request);
    }

    if ($this->attemptLogin($request)) {
        return $this->sendLoginResponse($request);
    }

    // If the login attempt was unsuccessful we will increment the number of attempts
    // to login and redirect the user back to the login form. Of course, when this
    // user surpasses their maximum number of attempts they will get locked out.
    $this->incrementLoginAttempts($request);

    return $this->sendFailedLoginResponse($request);
}

如您所见，该函数sendLoginResponse就是调用该authenticated函数的函数。

protected function sendLoginResponse(Request $request)
{
    $request->session()->regenerate();

    $this->clearLoginAttempts($request);

    return $this->authenticated($request, $this->guard()->user())
            ?: redirect()->intended($this->redirectPath());
}

因此，在您的情况下，应该重新生成会话并清除尝试：

return $this->sendLoginResponse($request);

或者，如果您想直接跳到已验证的功能，请执行以下操作：

return $this->authenticated($request, auth()->user());

您的函数应如下所示：

public function login(Request $request)
{
    if (Auth::attempt(['email' => $request->email, 'password' => $request->password, 'isActive' => '1']))
    {
        // Updated this line
        return $this->sendLoginResponse($request);

        // OR this one
        // return $this->authenticated($request, auth()->user());
    }
    else
    {
        return $this->sendFailedLoginResponse($request, 'auth.failed_status');
    }
}