将SQL查询转换为休眠标准和预测

Tal*_*lib 8 sql-server hibernate hql subquery hibernate-criteria

我从SQL查询:

select e.* 
from terminal_remote_deployment e
where id = (select top 1 e1.id
            from terminal_remote_deployment e1
            where e1.Terminal_info_id = e.Terminal_info_id
            order by e1.version desc
           );
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我试图在HQL中编写它,如下所示:

final StringBuilder hql = new StringBuilder();
            hql.append(" from TerminalRemoteDeployment e");
            hql.append(" where e.id = (Select TOP 1 e1.id from TerminalRemoteDeployment e1 where e1.terminalInfo.id = e.terminalInfo.id order by e1.version desc)");

            Query query = getEntityManager().createQuery(hql.toString());
            resultList = (List<TerminalRemoteDeployment>) query.getResultList();
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我遇到这种方法的错误.请帮我写一下hibernate的标准,因为我对此很新.

Tan*_*tia 3

第二个 Append 的内部子查询中的 Where 子句。它应该是terminal_Info_id而不是terminalInfo.id

final StringBuilder hql = new StringBuilder();
        hql.append(" from TerminalRemoteDeployment e");
        hql.append(" where e.id = (Select TOP 1 id from TerminalRemoteDeployment e1 where e1.terminal_Info_id = e.terminal_Info_id order by e1.version desc)");

        Query query = getEntityManager().createQuery(hql.toString());
        resultList = (List<TerminalRemoteDeployment>) query.getResultList();
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