如果返回0行,MySQL返回结果

Tom*_*Tom 3 php mysql

我有这个PHP代码:

$query = "SELECT name, COUNT(message) FROM guestbook_message WHERE name='".$req_user_info['username']."' GROUP BY name"; 

$result = mysql_query($query) or die(mysql_error());

while($row = mysql_fetch_array($result))
{
    echo "Messages posted: ". $row['COUNT(message)'] ."";
    echo "<br />";
}
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这将显示用户发布的评论数量.

如果该用户没有发布消息,如何使其返回值?目前显示什么都没有.但我希望它显示"消息发布:0"

有任何想法吗?

sha*_*mar 9

检查结果中返回的结果数量mysql_num_rows.

$query = "SELECT name, COUNT(message) FROM guestbook_message WHERE name='".$req_user_info['username']."' GROUP BY name"; 

$result = mysql_query($query) or die(mysql_error());

if(mysql_num_rows($result) > 0)
    while($row = mysql_fetch_array($result))
    {
       echo "Messages posted: ". $row['COUNT(message)'] ."";
       echo "<br />";
    }
else
    echo "NO Messages posted. <br />";
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  • 如果结果为0行,则会发出警告!PHP警告:mysql_num_rows()期望参数1为资源,布尔值在... (2认同)