使用石墨烯中继创建订阅

Bel*_*owa 0 graphql graphene-python graphql-subscriptions graphql-mutation

我是 graphQL 石墨烯(python)的新手。我想知道是否可以使用石墨烯创建订阅根类型。谢谢

Yac*_*ali 6

这绝对是可能的。您可以在此处找到有关如何执行此操作的示例:https : //github.com/graphql-python/graphql-ws

这是该仓库中的一个示例:

import asyncio
import graphene


class Query(graphene.ObjectType):
    base = graphene.String()


class Subscription(graphene.ObjectType):
    count_seconds = graphene.Float(up_to=graphene.Int())

    async def resolve_count_seconds(root, info, up_to):
        for i in range(up_to):
            yield i
            await asyncio.sleep(1.)
        yield up_to


schema = graphene.Schema(query=Query, subscription=Subscription)
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  • 这在执行期间给了我以下错误:`Subscription must return Async Iterable or Observable。收到:<async_generator object ... at ...>'` (6认同)