不使用构造函数将StatefulWidget数据传递给State类

Bla*_*nka 3 dart flutter

我设法通过如下构造函数将有状态类变量的值传递给State类:

import 'package:flutter/material.dart';

void main() => runApp(MyApp());

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
        title: 'Demo',
        home: MyHomePage('John', 'Morison'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  _MyHomePageState createState() => _MyHomePageState(fname, lname);
}

class _MyHomePageState extends State<MyHomePage> {
  _MyHomePageState(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: Center(
        child: Text('Hello $fname $lname'),
      )
    );
  }
}
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太奇怪了,因为有两个以上的变量,所以我不得不做很多工作。有没有更好的办法?

Bla*_*nka 6

是的,有widget

从文档:

  /// The current configuration.
  ///
  /// A [State] object's configuration is the corresponding [StatefulWidget]
  /// instance. This property is initialized by the framework before calling
  /// [initState]. If the parent updates this location in the tree to a new
  /// widget with the same [runtimeType] and [Widget.key] as the current
  /// configuration, the framework will update this property to refer to the new
  /// widget and then call [didUpdateWidget], passing the old configuration as
  /// an argument.
  T get widget => _widget;
  T _widget;
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代码如下所示:

import 'package:flutter/material.dart';

void main() => runApp(MyApp());

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
        title: 'Demo',
        home: MyHomePage('John', 'Morison'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage(this.fname, this.lname);

  final String fname;
  final String lname;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: Center(
        child: Text('Hello ${widget.fname} ${widget.lname}'),
      )
    );
  }
}
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  • 我完全不明白这一点。您将状态存储在小部件中,并将 UI 构建存储在状态中。这完全倒退到了对象的命名方式。 (2认同)