更改计算器仅在需要一种类型的硬币时才有效

Ale*_*ith 4 python python-2.7

我目前正在尝试学习python并且已经在/ r/learnpython上进行了初学者项目.我对更改计算器项目的想法是创建一个包含键'quarter','dime','nickel'和'penny'的字典,每个字符的值都初始化为0.我的代码,如下所示,似乎只在改变我输入只需要一种类型的硬币,即0.75 - > 3季度,0.1 - > 1角钱等.

 change_map = {
    'quarter' : 0,
    'dime' : 0,
    'nickel' : 0,
    'penny' : 0
}

def calculator(change):
    while change > 0:
        if change >= 0.25:
            change -= 0.25
            change_map['quarter'] += 1
        elif change < 0.25 and change >= 0.10:
            change -= 0.10
            change_map['dime'] += 1
        elif change < 0.10 and change >= 0.05:
            change -= 0.05
            change_map['nickel'] += 1
        elif change < 0.05 and change >= 0.01:
            change -= 0.01
            change_map['penny'] += 1
    print "You need the following: "
    print change_map

change = raw_input("Please enter amount of change: ")
change = float(change)
calculator(change)
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Oli*_*çon 5

浮点算术错误

您的错误是由浮点算术错误引起的.以下是输入诸如的值时会发生的情况0.26.

change = 0.26
change  -= 0.25
change  -= 0.01
print (change) # 8.673617379884035e-18
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由于最后一个值change高于0但低于0.01,您将进入无限循环.

如何解决它

解决此问题的一种方法是依靠精确算术,int而不是float代表货币等离散值.这意味着使你的基本单位成为美分而不是美元.

change_map = {
    'quarter' : 0,
    'dime' : 0,
    'nickel' : 0,
    'penny' : 0
}

def calculator(change):
    while change > 0:
        if change >= 25:
            change -= 25
            change_map['quarter'] += 1
        elif change >= 10:
            change -= 10
            change_map['dime'] += 1
        elif change >= 5:
            change -= 5
            change_map['nickel'] += 1
        else:
            change -= 1
            change_map['penny'] += 1

    print ("You need the following: ")
    print (change_map)

change = raw_input("Please enter amount of change: ")

# Here we convert the decimal value input by the user to cents
change = int(float(change) * 100)

calculator(change)
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例:

Please enter amount of change: 0.26
You need the following: 
{'quarter': 1, 'dime': 0, 'nickel': 0, 'penny': 1}
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改进

另外,您可以使用dict硬币的值和名称来改进解决方案.特别是,这允许您通过更新dict而不必添加新的if语句来扩展程序.

这是一个增加美元作为变化的可能性的例子.

value_map = {
    100: 'dollar',
    25: 'quarter',
    10: 'dime',
    5: 'nickel',
    1: 'penny'
}

def calculator(change):
    change_map = {}

    for value in sorted(value_map, reverse=True):
        coin = value_map[value]
        change_map[coin], change = divmod(change, value)

    print ("You need the following: ")
    print (change_map)

change = raw_input("Please enter amount of change: ")

change = int(float(change) * 100)

calculator(change)
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