如何单独更新`BehaviorSubject`单值

Question

在我BehaviorSubject的地址元素具有2属性。在此如何单独更新单个属性？

这是我的尝试：

myAddress:any = {
    "plot":32,
    "street":"D15 Road"
  }

  private address = new BehaviorSubject(this.myAddress);
  addressClass = this.address.asObservable();


  updateAddress(newAddress){
    this.address.next(newAddress);
  }

我正在尝试这样更新：

import { Component, Input, OnInit } from '@angular/core';
import { SharedObject } from './shared.object';

@Component({
  selector: 'hello',
  template: `
    <h1>Hello {{name}}!</h1>
    <h2>City Name in Hero : {{heroName}}</h2>
    <h3>{{plotNo}}</h3>
    <button (click)="updatePlot(44)">Update Ploat </button>
  `,
  styles: [`h1 { font-family: Lato; }`]
})
export class HelloComponent  {

  @Input() name: string;

  plotNo:number;
  address:any;


  constructor(private shared:SharedObject){

  }

  ngOnInit(){
     this.shared.addressClass.subscribe((address) => {
       this.plotNo = address.plot;
     })
  }


  updatePlot(newNo){
    this.shared.updateAddress(newNo); //don't know how to update plot no alone?
  }

}

Answer 1

您可以使用传播算子和BehaviorSubjects值，如下所示：

updateAddress(newAddress){
  this.address.next({...this.address.value, ...newAddress});
}

这是一个stackblitz演示。