您可以使用符号工具箱来计算大整数.
下面是一些我编写的用于绘制Tupper表达式的代码,部分受到metafilter讨论的启发:
% use the symbolic toolbox to represent the big integer k
k = sym(['960939379918958884971672962127852754715004339660129306651505519271702802395266424689642842174350' ...
'718121267153782770623355993237280874144307891325963941337723487857735749823926629715517173716995' ...
'165232890538221612403238855866184013235585136048828693337902491454229288667081096184496091705183' ...
'454067827731551705405381627380967602565625016981482083418783163849115590225610003652351370343874' ...
'461848378737238198224849863465033159410054974700593138339226497249461751545728366702369745461014' ...
'655997933798537483143786841806593422227898388722980000748404719']);
[x,y] = meshgrid(0:1:106, 0:1:16);
% evaluate the tupper formula
tupper = rem(floor(floor((y+k)/17) .* 2.^(-17*x - rem((y+k), 17))), 2);
% convert from symbolic to Matlab's native double precision
tupper = double(tupper);
% display it!
image(fliplr((1-tupper)*255));
colormap gray
axis equal
title('Tupper''s (not-so-)self-referential formula!');
set(gca, 'XTick', [], 'YTick', []);
Run Code Online (Sandbox Code Playgroud)
结果如下:

注意:关于公式实际上没有任何自我指涉; 通过选择差值k,可以使其显示相同大小的任何其他图像.如果它是一个真正的quine会更令人兴奋!