使用 Jenkins 管道解压缩文件

Question

我有一个名为 ***.zip 的 zip 文件。我使用下面的命令来解压缩它。一旦我解压，里面的文件也是“Zip”文件（超过3个zip文件）。您能否让我知道如何解压这些文件？

unzip zipFile: "$project_version",dir:"D:\\jenkins\\DEV\\extract\\project", quiet: true

尝试做-

unzip dir: 'D:\\jenkins\\DEV\\extract\\project', glob: '', zipFile: 'D:\\jenkins\\DEV\\extract\\project\\project_*.zip'

错误日志

java.io.IOException: D:\jenkins\DEV\extract\project\project_*.zip does not exist.
    at org.jenkinsci.plugins.pipeline.utility.steps.zip.UnZipStepExecution.run(UnZipStepExecution.java:77)
    at org.jenkinsci.plugins.workflow.steps.AbstractSynchronousNonBlockingStepExecution$1$1.call(AbstractSynchronousNonBlockingStepExecution.java:47)
    at hudson.security.ACL.impersonate(ACL.java:260)
    at org.jenkinsci.plugins.workflow.steps.AbstractSynchronousNonBlockingStepExecution$1.run(AbstractSynchronousNonBlockingStepExecution.java:44)
    at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511)
    at java.util.concurrent.FutureTask.run(FutureTask.java:266)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
    at java.lang.Thread.run(Thread.java:745)
Finished: FAILURE

解压主 zip 文件后我的目录下的文件。

05/16/2018  04:31 PM    <DIR>          .
05/16/2018  04:31 PM    <DIR>          ..
05/15/2018  12:51 PM           265,637 project-project1_1.0.0.24_bdd86e0c.zip
05/15/2018  12:51 PM         7,924,188 project-project2_1.4.0.130_43dce5e4.zip
05/15/2018  12:51 PM         6,862,842 project-project3_1.0.0.207_c7d5d471.zip
               3 File(s)     15,052,667 bytes
               2 Dir(s)  432,451,330,048 bytes free

我需要在 Windows 中类似的命令-

for file in `ls 123_*.zip'; do unzip $file -d `echo $file | cut -d "." -f 1`; done

Answer 1

您可以在步骤块中使用管道实用程序步骤，该步骤应适用于脚本化和声明式管道样式

steps {
      unzip zipFile: 'file.zip', dir: '<directory>'
}