spring中嵌套配置属性的前缀

Bye*_*Bye 6 java spring spring-boot

Spring Boot 2.0.0.RELEASE

我有属性类:

@Configuration
@ConfigurationProperties(prefix="person")
public class PersonProperties {

    private AddressProperties addressProperties;

    public AddressProperties getAddressProperties() {
        return addressProperties;
    }

    public void setAddressProperties(final AddressProperties addressProperties) {
        this.addressProperties = addressProperties;
    }

    public static class AddressProperties {

        private String line1;

        public String getLine1() {
            return line1;
        }

        public void setLine1(final String line1) {
            this.line1 = line1;
        }
    }

}
Run Code Online (Sandbox Code Playgroud)

并且application.yml

person:
  address:
    line1: line1OfAddress
Run Code Online (Sandbox Code Playgroud)

它没有像我的AddressProperties对象那样正确绑定null。当一个类与 yml 属性具有相同的名称时AddressProperties->Address它运行良好。我试图添加QualifierConfigurationProperties前缀,address但它不起作用。不幸的是,我在 spring 文档中找不到有关此案例的有用信息。

如何为嵌套属性指定前缀?

Pra*_*tel 3

yaml/属性文件中定义的属性应与类中定义的变量匹配。将 yaml 文件更改为

person:
  # addressProperties will also work here
  address-properties:
    line1: line1OfAddress
Run Code Online (Sandbox Code Playgroud)

或者将你的bean定义为

@Configuration
@ConfigurationProperties(prefix = "person")
public class PersonProperties {

    // here variable name doesn't matter, it can be addressProperties as well
    // setter / getter should match with properties in yaml
    // i.e. getAddress() and setAddress()
    private AddressProperties address;

    public AddressProperties getAddress() {
        return address;
    }

    public void setAddress(AddressProperties address) {
        this.address = address;
    }
}
Run Code Online (Sandbox Code Playgroud)

如果您想获取地址下的所有属性而不在单独的 bean 中定义它们,您可以将您的PersonProperties类定义为

@Configuration
@ConfigurationProperties(prefix = "person")
public class PersonProperties {

    private Map<String, Object> address;

    public Map<String, Object> getAddress() {
        return address;
    }

    public void setAddress(Map<String, Object> address) {
        this.address = address;
    }
}
Run Code Online (Sandbox Code Playgroud)

这里PersonProperties#address将包含{line1=line1OfAddress}

现在,地址下的所有属性都将位于Map.

  • @ByeBye 请注意,您不必将嵌套类命名为与 YAML 相同的名称,只需将属性本身命名即可。甚至实例变量名称也不必与 YAML 匹配——只有 getter 和 setter 需要匹配。因此,Hemant 的第二个建议('private void setAdddress(AddressProperties address)`)似乎可以满足您的需求,即使它不是您所希望的基于注释的解决方案。 (4认同)