fly*_*ina 4 xstream xml-serialization
我正在使用XStream来序列化和反序列化对象.例如,一个名为的类Rating定义如下:
Public Class Rating {
String id;
int score;
int confidence;
// constructors here...
}
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但是,在此类中,变量confidence是可选的.
因此,当置信度值(非0)时,Rating对象的XML表示应如下所示:
<rating>
<id>0123</id>
<score>5</score>
<confidence>10</confidence>
</rating>
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但是,当置信度未知(默认值为0)时,应从XML表示中省略置信属性:
<rating>
<id>0123</id>
<score>5</score>
</rating>
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谁能告诉我如何使用XStream有条件地序列化字段?
一种选择是编写转换器.
这是我很快为你写的:
import com.thoughtworks.xstream.converters.Converter;
import com.thoughtworks.xstream.converters.MarshallingContext;
import com.thoughtworks.xstream.converters.UnmarshallingContext;
import com.thoughtworks.xstream.io.HierarchicalStreamReader;
import com.thoughtworks.xstream.io.HierarchicalStreamWriter;
public class RatingConverter implements Converter
{
@Override
public boolean canConvert(Class clazz) {
return clazz.equals(Rating.class);
}
@Override
public void marshal(Object value, HierarchicalStreamWriter writer,
MarshallingContext context)
{
Rating rating = (Rating) value;
// Write id
writer.startNode("id");
writer.setValue(rating.getId());
writer.endNode();
// Write score
writer.startNode("score");
writer.setValue(Integer.toString(rating.getScore()));
writer.endNode();
// Write confidence
if(rating.getConfidence() != 0)
{
writer.startNode("confidence");
writer.setValue(Integer.toString(rating.getConfidence()));
writer.endNode();
}
}
@Override
public Object unmarshal(HierarchicalStreamReader arg0,
UnmarshallingContext arg1)
{
return null;
}
}
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剩下的就是注册转换器,并在Rating类中提供访问器方法(即getId,getScore,getConfidence).
注意:您的另一个选择是适当地省略该字段.
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