MySql查询同一表以收集到期日和年初至今的信息

Question

尽管我确信有一个简单的答案,但我一直在努力解决这个问题几个小时.我正在尝试从同一个表中收集月度信息和年初至今的信息.我也加入了第二张桌来收集团体名称.

费用表:

+-----------------+---------------+------+-----+---------+----------------+
| Field           | Type          | Null | Key | Default | Extra          |
+-----------------+---------------+------+-----+---------+----------------+
| id              | int(5)        | NO   | PRI | NULL    | auto_increment |
| account         | char(14)      | NO   |     | NULL    |                |
| batch           | int(5)        | NO   |     | NULL    |                |
| date            | date          | NO   |     | NULL    |                |
| description     | varchar(50)   | NO   |     | NULL    |                |
| debit           | decimal(10,2) | NO   |     | NULL    |                |
| credit          | decimal(10,2) | NO   |     | NULL    |                |
| account_data_id | varchar(14)   | NO   |     | NULL    |                |
+-----------------+---------------+------+-----+---------+----------------+

account_data表:

+--------------+-------------+------+-----+---------+----------------+
| Field        | Type        | Null | Key | Default | Extra          |
+--------------+-------------+------+-----+---------+----------------+
| id           | int(5)      | NO   | PRI | NULL    | auto_increment |
| account_code | varchar(14) | NO   |     | NULL    |                |
| group_name   | varchar(30) | NO   |     | NULL    |                |
+--------------+-------------+------+-----+---------+----------------+

我可以很容易地提出每月或年初的信息,但无论我做什么,我都无法兼得.下面是我能提出的最接近的,但是执行起来需要永远,结果不是预期的结果:

SELECT account_data.group_name, sum(m.debit)- sum(m.credit) AS month, sum(y.debit)- SUM(y.credit) AS year
FROM account_data
INNER JOIN expense m ON m.account_data_id = account_data.id
AND MONTH(m.`date`) IN (7,8,9,10,11,12)
LEFT JOIN expense y ON y.account_data_id = account_data.id
AND MONTH(y.`date`) IN (7)
GROUP BY account_data.group_name

这就是我想要完成的事情:

+--------------+----------+---------+
| group_name   | month    | year    | 
+--------------+----------+---------+
| Payroll      | 10,000   | 50,000  |
| Payroll Tax  | 1,000    | 5,000   |
| Benefits     | 500      | 1,000   |  
+--------------+----------+---------+

任何帮助是极大的赞赏.我是新来的,我希望我遵守所有规则,并为你们提供足够的信息来帮助,但如果没有让我知道,我会提供更多.

@philwinkle-您的解决方案,已正确修改:

SELECT ad.group_name,
IF(MONTH(e.date) IN (7,8,9,10,11,12), SUM(e.debit) - SUM(e.credit),'' ),
IF(MONTH(e.date) = 7, SUM(e.debit) - SUM(e.credit),'' )
FROM account_data ad
LEFT JOIN expense_2011 e ON e.account_data_id = ad.id
WHERE e.account_data_id > 7
GROUP BY ad.group_name

Answer 1

这里的解决方案是使用条件总和...我将放置伪代码，当我 100% 肯定时，我将编辑以下解决方案验证并有效：

SELECT ad.group_name,
(if(e.account_data_id IN (7,8,9,10,11,12),sum(e.debit)- sum(e.credit)) AS month,
(if(e.account_data_id=7,sum(e.debit)- sum(e.credit)) AS year
FROM account_data ad
LEFT JOIN expense e ON e.account_data_id = ad.id
WHERE e.account_data_id > 7
GROUP BY account_data.group_name