Sim*_*uto 6 python tk-toolkit tkinter python-3.x
我有一个按钮可以在我的代码上打开一个新窗口,我一直在尝试使该按钮打开一个名为“newest_release_window”的新窗口,并考虑到两件事:
不幸的是,它变得太复杂了,我一生都无法弄清楚如何去做。问题是我无法让代码检测“newest_release_window”是否打开,并据此更改变量。
welcome_window = Tk()
welcome_window.title("Games R Us")
welcome_window.geometry("360x350")
welcome_window.configure(bg = "gold")
currentDisplay = 10
newest_release_windowtracker = 0
gui_font_5 = ("Helvetica", 5, "bold")
gui_font_10 = ("Helvetica", 10, "bold")
gui_font_15 = ("Helvetica", 15, "bold")
gui_font_20 = ("Helvetica", 20, "bold")
space_between = (5)
button_variable = IntVar()
def newwindow_newest_release():
global newest_release_windowtracker
newest_release_window = Tk()
newest_release_window.title("Games R Us")
newest_release_window.geometry("360x350")
newest_release_window.configure(bg = "greenyellow")
currentDisplay = 10
display = Label(newest_release_window, text="Humm, see a new window !",
bg ="limegreen")
display.pack()
newest_release_window.withdraw()
if newest_release_windowtracker == 0:
newest_release_window.deiconify()
newest_release_windowtracker = 1
elif newest_release_windowtracker == 1:
newest_release_window.focus_set()
elif newest_release_window.winfo_exists == 0:
newest_release_window = Tk()
ww_newest_release = Button(welcome_window,
text = "Newest Release", bg = "goldenrod", font = "Helvetica 10",
width = 12, command = newwindow_newest_release)
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注意:这不是完整的代码,我只是抓住了最重要的部分来说明问题可能是什么。
您可以设置一个 bool 定义窗口是否打开,如果打开,则调用orlift()实例上的方法。tkinter.Tktkinter.Toplevel
检查窗口是否存在:如果窗口上方
存在根newest_release类,则可以检查hasattr(base_class, 'newest_release'). 如果没有,那么您可以将这样的窗口设置global newest_release为全局变量,以便您可以在函数外部访问它。然后你可以创建这样的代码:
if 'newest_release' in globals():
newest_release.lift()
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或者
if hasattr(base_class, 'newest_release'):
newest_release.lift()
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