TypeScript模块扩充

Question

我有可观察的扩展.它工作得很好,但现在我已经更新到角度为6的打字稿2.7.2.

import { Observable } from 'rxjs/Observable';
import { BaseComponent } from './base-component';
import { Subscription } from 'rxjs/Subscription';
import { Subscribable } from 'rxjs';

declare module 'rxjs/Observable' {
    export interface Observable<T> {
        safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
            next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription;
    }
}


export function safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
    next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription {
    let sub = this.subscribe(next, error, complete);
    component.markForSafeDelete(sub);
    return sub;
}

Observable.prototype.safeSubscribe = safeSubscribe;

这段代码不起作用

1. 'Observable'仅指类型,但在此处用作值.
2. 属性'subscribe'在'Observable'类型上不存在.

https://www.typescriptlang.org/docs/handbook/declaration-merging.html

Answer 1

合并声明时,指定的模块路径必须与实际模块的路径完全匹配.

使用RxJS版本6,您将需要更改模块声明,因为内部结构已更改.从记忆中,它应该是:

declare module 'rxjs/internal/Observable' {
    export interface Observable<T> {
        safeSubscribe<T>(this: Observable<T>, component: BaseComponent,
            next?: (value: T) => void, error?: (error: T) => void, complete?: () => void): Subscription;
    }
}

举一个例子,看到修补进口的一个在rxjs-compat.