Clá*_*ida 22 post json dart flutter
这是我向API发出请求的代码:
import 'dart:async';
import 'dart:convert';
import 'dart:io';
import 'package:http/http.dart' as http;
Future<http.Response> postRequest () async {
var url ='https://pae.ipportalegre.pt/testes2/wsjson/api/app/ws-authenticate';
var body = jsonEncode({ 'data': { 'apikey': '12345678901234567890' } });
print("Body: " + body);
http.post(url,
headers: {"Content-Type": "application/json"},
body: body
).then((http.Response response) {
print("Response status: ${response.statusCode}");
print("Response body: ${response.contentLength}");
print(response.headers);
print(response.request);
});
}
我对请求的响应有一个问题,它假设有一个带json的主体,但是出了点问题,我认为是我在body请求上发送的json,因为它是一个嵌套的json对象,并且key的值是json对象.我很想知道如何解析json并插入到请求的正文中.
这是标题响应:
{set-cookie: JSESSIONID=DA65FBCBA2796D173F8C8D78AD87F9AD;path=/testes2/;HttpOnly, last-modified: Thu, 10 May 2018 17:15:13 GMT, cache-control: no-store, no-cache, must-revalidate, max-age=0, post-check=0, pre-check=0, date: Thu, 10 May 2018 17:15:13 GMT, content-length: 0, pragma: no-cache, content-type: text/html, server: Apache-Coyote/1.1, expires: Tue, 03 Jul 2001 06:00:00 GMT}
这就是假设:
Server: Apache-Coyote/1.1
Expires: Tue, 03 Jul 2001 06:00:00 GMT
Last-Modified: Thu, 10 May 2018 17:17:07 GMT
Cache-Control: no-store, no-cache, must-revalidate, max-age=0, post-check=0, pre-check=0
Pragma: no-cache
Content-Type: application/json;charset=UTF-8
Vary: Accept-Encoding
Set-Cookie: JSESSIONID=84813CC68E0E8EA6021CB0B4C2F245BC;path=/testes2/;HttpOnly
Keep-Alive: timeout=5, max=100
Connection: Keep-Alive
Transfer-Encoding: chunked
身体反应是空的,我认为它是因为我发送请求的身体,任何人都可以帮助我在嵌套的json对象的价值？
Raj*_*dav 33
这可行！
import 'dart:async';
import 'dart:convert';
import 'dart:io';
import 'package:http/http.dart' as http;
Future<http.Response> postRequest () async {
var url ='https://pae.ipportalegre.pt/testes2/wsjson/api/app/ws-authenticate';
Map data = {
'apikey': '12345678901234567890'
}
//encode Map to JSON
var body = json.encode(data);
var response = await http.post(url,
headers: {"Content-Type": "application/json"},
body: body
);
print("${response.statusCode}");
print("${response.body}");
return response;
}
Ric*_*eap 24
好的,最后我们有答案......
您正在指定headers: {"Content-Type": "application/json"},设置内容类型.在引擎盖下,无论是封装http还是较低级别dart:io HttpClient都将其更改为application/json; charset=utf-8.但是,您的服务器Web应用程序显然不期望后缀.
为了证明这一点,我在Java中试用了两个版本
conn.setRequestProperty("content-type", "application/json; charset=utf-8"); // fails
conn.setRequestProperty("content-type", "application/json"); // works
您是否可以联系Web应用程序所有者来解释他们的错误？我无法看到Dart添加后缀的位置,但我会稍后再看.
编辑
后来的调查表明,这是一个http包,虽然为你做了很多繁重的工作,但是添加了服务器不喜欢的后缀.如果您无法让他们修复服务器,那么您可以绕过http并dart:io HttpClient直接使用它.你最终会得到一些通常为你处理的样板文件http.
下面的工作示例:
import 'dart:convert';
import 'dart:io';
import 'dart:async';
main() async {
String url =
'https://pae.ipportalegre.pt/testes2/wsjson/api/app/ws-authenticate';
Map map = {
'data': {'apikey': '12345678901234567890'},
};
print(await apiRequest(url, map));
}
Future<String> apiRequest(String url, Map jsonMap) async {
HttpClient httpClient = new HttpClient();
HttpClientRequest request = await httpClient.postUrl(Uri.parse(url));
request.headers.set('content-type', 'application/json');
request.add(utf8.encode(json.encode(jsonMap)));
HttpClientResponse response = await request.close();
// todo - you should check the response.statusCode
String reply = await response.transform(utf8.decoder).join();
httpClient.close();
return reply;
}
根据您的使用情况,重新使用HttpClient可能更有效,而不是为每个请求继续创建新的HttpClient.Todo - 添加一些错误处理;-)
这也可以工作：
import 'package:http/http.dart' as http;
sendRequest() async {
Map data = {
'apikey': '12345678901234567890'
};
var url = 'https://pae.ipportalegre.pt/testes2/wsjson/api/app/ws-authenticate';
http.post(url, body: data)
.then((response) {
print("Response status: ${response.statusCode}");
print("Response body: ${response.body}");
});
}
这对我有用
String body = json.encode(parameters);
http.Response response = await http.post(
url: 'https://example.com',
headers: {"Content-Type": "application/json"},
body: body,
);
我想很多人都对 Post'Content-type': 'application / json'
有问题这里的问题是将数据解析Map <String, dynamic>为json：
希望下面的代码可以帮助某人
模型：
class ConversationReq {
String name = '';
String description = '';
String privacy = '';
String type = '';
String status = '';
String role;
List<String> members;
String conversationType = '';
ConversationReq({this.type, this.name, this.status, this.description, this.privacy, this.conversationType, this.role, this.members});
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = new Map<String, dynamic>();
data['name'] = this.name;
data['description'] = this.description;
data['privacy'] = this.privacy;
data['type'] = this.type;
data['conversations'] = [
{
"members": members,
"conversationType": conversationType,
}
];
return data;
}
}
要求：
createNewConversation(ConversationReq param) async {
HeaderRequestAuth headerAuth = await getAuthHeader();
var headerRequest = headerAuth.toJson();
/*
{
'Content-type': 'application/json',
'x-credential-session-token': xSectionToken,
'x-user-org-uuid': xOrg,
}
*/
var bodyValue = param.toJson();
var bodydata = json.encode(bodyValue);// important
print(bodydata);
final response = await http.post(env.BASE_API_URL + "xxx", headers: headerRequest, body: bodydata);
print(json.decode(response.body));
if (response.statusCode == 200) {
// TODO
} else {
// If that response was not OK, throw an error.
throw Exception('Failed to load ConversationRepo');
}
}
我是这样实现的：
static createUserWithEmail(String username, String email, String password) async{
var url = 'http://www.yourbackend.com/'+ "users";
var body = {
'user' : {
'username': username,
'address': email,
'password': password
}
};
return http.post(
url,
body: json.encode(body),
headers: {
"Content-Type": "application/json"
},
encoding: Encoding.getByName("utf-8")
);
}