nan*_*eri 5 mysql laravel eloquent
我有一个包含以下关系的数据库:
有projects- 人们可以购买的东西,也有user_id,
有backers- 购买的人,
有orders-每个订单是一个购买的Project由Backer(Backer只能购买各Project一次).这是一笔金额 - 显示Backer购买该金额的金额Project
我需要的是写下面的查询 - 给定$user_id,$count并$sum找到所有投资至少在$count项目数量上user_id等于$user_id并且具有高于那些项目的购买总和的所有支持者$sum.
Backer::whereHas('projects', function ($q) use ($sum, $userId){
$q->where('user_id', $userId);
}, '>=', $leastProjectCount)->get();
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但它并不限制$sum购买
更新: 所以我提出了这个问题:
select * from `backers` \r\n
WHERE id > 0 \r\n
AND (select count(*)\r\n
FROM `projects` \r\n
inner join `orders` on `projects`.`id` = `orders`.`project_id` \r\n
where `backers`.`id` = `orders`.`backer_id` \r\n
and `user_id` = 6 \r\n
and exists (\r\n
select * \r\n
from `tags` \r\n
inner join `project_tag` on `tags`.`id` = `project_tag`.`tag_id` \r\n
where `projects`.`id` = `project_tag`.`project_id` \r\n
and `id` in (27)\r\n
) \r\n
) >= 1 \r\n
AND (select sum(orders.amount)\r\n
FROM `projects` \r\n
inner join `orders` on `projects`.`id` = `orders`.`project_id` \r\n
where `backers`.`id` = `orders`.`backer_id` \r\n
and `user_id` = 6 \r\n
and exists (\r\n
select * \r\n
from `tags` \r\n
inner join `project_tag` on `tags`.`id` = `project_tag`.`tag_id` \r\n
where `projects`.`id` = `project_tag`.`project_id` \r\n
and `id` in (27)\r\n
) \r\n
) >= 12
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请注意,子查询几乎相同,只是第一次使用COunt(*)和第二次使用sum(orders.amount).并且还要注意,如果设置了所有参数,则运行此查询,但是如果未设置某些参数,则可以更短.我得到的问题是我没有这样的查询分页.
尝试这个:
Backer::whereHas('projects', function ($q) use ($sum, $userId){
$q->where('user_id', $userId)
->havingRaw('SUM(amount) > ? ', [$sum]);
}, '>=', $leastProjectCount)->get();
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