Jad*_*ias 21 arrays matlab matrix
给定一个数组:
array1 = [1 2 3];
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我必须这样扭转它:
array1MirrorImage = [3 2 1];
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到目前为止,我获得了这个丑陋的解
array1MirrorImage = padarray(array1, [0 length(array1)], 'symmetric', 'pre');
array1MirrorImage = array1MirrorImage(1:length(array1));
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有更漂亮的解决方案吗?
gno*_*ice 31
更新:在较新版本的MATLAB(R2013b及更高版本)中,最好使用函数flip代替flipdim,它具有相同的调用语法:
a = flip(a, 1); % Reverses elements in each column
a = flip(a, 2); % Reverses elements in each row
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托马斯有正确的答案.要添加一点,您还可以使用更一般的flipdim:
a = flipdim(a, 1); % Flips the rows of a
a = flipdim(a, 2); % Flips the columns of a
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另外一个小技巧......如果由于某种原因你必须翻转2-D数组的两个尺寸,你可以调用flipdim两次:
a = flipdim(flipdim(a, 1), 2);
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或致电rot90:
a = rot90(a, 2); % Rotates matrix by 180 degrees
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Sco*_*e T 19
另一个简单的解决方案
b = a(end:-1:1);
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您也可以在特定维度上使用它.
b = a(:,end:-1:1); % Flip the columns of a
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Tom*_*han 14
您可以使用
rowreverse = fliplr(row) % for a row vector (or each row of a 2D array)
colreverse = flipud(col) % for a column vector (or each column of a 2D array)
genreverse = x(end:-1:1) % for the general case of a 1D vector (either row or column)
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