LB4*_*B40 60 python beautifulsoup
我想获取<script>文档中的所有标记,然后根据某些属性的存在(或不存在)处理每个标记.
例如,对于每个<script>标签,如果属性for存在,则执行某些操作; 否则,如果属性bar存在,则执行其他操作.
这是我目前正在做的事情:
outputDoc = BeautifulSoup(''.join(output))
scriptTags = outputDoc.findAll('script', attrs = {'for' : True})
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但是这样我<script>用for属性过滤所有标签......但是我丢失了其他标签(那些没有for属性的标签).
Luc*_* S. 82
如果我理解得很好,你只需要所有的脚本标签,然后检查它们中的一些属性?
scriptTags = outputDoc.findAll('script')
for script in scriptTags:
if script.has_attr('some_attribute'):
do_something()
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mia*_*iah 29
为了将来参考,has_key已被弃用是beautifulsoup 4.现在你需要使用has_attr
scriptTags = outputDoc.findAll('script')
for script in scriptTags:
if script.has_attr('some_attribute'):
do_something()
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Pad*_*ham 20
你不需要任何lambda按属性过滤,你只需要设置some_attribute=True等..:
script_tags = soup.find_all('script', some_attribute=True)
# or
script_tags = soup.find_all('script', {"some-data-attribute": True})
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你也可以使用re和find/find_all等..:
soup = bs4.BeautifulSoup(html)
# Find all with a specific attribute
tags = soup.find_all(src=True)
tags = soup.select("[src]")
# Find all meta with either name or http-equiv attribute.
soup.select("meta[name],meta[http-equiv]")
# find any tags with any name or source attribute.
soup.select("[name], [src]")
# find first/any script with a src attribute.
tag = soup.find('script', src=True)
tag = soup.select_one("script[src]")
# find all tags with a name attribute beginning with foo
# or any src beginning with /path
soup.select("[name^=foo], [src^=/path]")
# find all tags with a name attribute that contains foo
# or any src containing with whatever
soup.select("[name*=foo], [src*=whatever]")
# find all tags with a name attribute that endwith foo
# or any src that ends with whatever
soup.select("[name$=foo], [src$=whatever]")
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小智 14
如果您只需要获取带有属性的标记,则可以使用lambda:
soup = bs4.BeautifulSoup(YOUR_CONTENT)
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tags = soup.find_all(lambda tag: 'src' in tag.attrs)
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要么
tags = soup.find_all(lambda tag: tag.has_attr('src'))
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tag = soup.find(lambda tag: tag.name == 'script' and 'src' in tag.attrs)
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认为它可能有用.