如何获取结果集的最后一行中所有列值的总和？

Question

我需要获取最后一行中结果集的所有列值的总和.
这是我的SQL查询.

select Master_Code, SUM(Jan), SUM(Feb), SUM(Mar)
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code ORDER BY Master_Code ASC

这样的事情:

    Master_Code Jan Feb Mar 
    1            4   5   6
    2            5   5   5
    Total        9  10  11

Answer 1

建立一个联合,您重复相同的查询,但没有分组:

select Title, Jan, Feb, Mar
from (
  select Master_Code as Title, SUM(Jan) as Jan, SUM(Feb) as Feb, SUM(Mar) as Mar
  from dbo.foobar
  WHERE Participating_City = 'foofoo'
  GROUP BY Master_Code ORDER BY Master_Code ASC
) x
union all
select 'Total', SUM(Jan) as Jan, SUM(Feb) as Feb, SUM(Mar) as Mar
from dbo.foobar
WHERE Participating_City = 'foofoo'

Answer 2

假设没有null master_code行.

SELECT ISNULL(Master_code, 'Total') AS Master_Code,
       Jan,
       Feb,
       Mar
FROM (
      SELECT Master_code,
             SUM(Jan) AS Jan,
             SUM(Feb) AS Feb,
             SUM(Mar) AS Mar
      FROM foobar
      WHERE Participating_City = 'foofoo'
      GROUP BY Master_code WITH ROLLUP
     ) AS DT

Answer 3

您还可以使用 Coalesce 和 With Rollup。

SELECT COALESCE(Master_Code, 'TOTAL') AS MASTER_CODE, SUM(Jan), SUM(Feb), SUM(Mar)
FROM dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code WITH ROLLUP
ORDER BY Master_Code DESC