zin*_*rim 4 java generics comparator java-8
我想通过键(String类型)对Type AVLNode的对象进行排序.我实例化了一个Comparator,并希望compareTo在String属性上应用Method.但是,我的IDE显示错误Cannot resolve method compareTo.我不明白为什么我不能compareTo在字符串上使用这个方法.
import java.util.*;
public class AVLTreeTest {
public static void main(String[] args){
Comparator<AVLNode>myComp2 = new Comparator<AVLNode>() {
@Override public int compare(AVLNode n1, AVLNode n2) {
return n1.getKey().compareTo(n2.getKey());
}
};
AVLNode<String, AVLNode> a1 = new AVLNode( "test3", new Cuboid (2,3,4,5,6,7) );
AVLNode<String, AVLNode> a2 = new AVLNode( "test2", new Cuboid (2,3,4,5,6,7) );
AVLNode<String, AVLNode> a3 = new AVLNode( "test8", new Cuboid (2,3,4,5,6,7) );
AVLNode<String, AVLNode> a4 = new AVLNode( "test1", new Cuboid (2,3,4,5,6,7) );
List<AVLNode> listOfNodes = new ArrayList<AVLNode>();
listOfNodes.add(a1);
listOfNodes.add(a2);
listOfNodes.add(a3);
listOfNodes.add(a4);
Collections.sort(listOfNodes, myComp2);
for (AVLNode node : listOfNodes){
System.out.println(node);
}
}
}
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这是我的AVLNode类
public class AVLNode<K, V> {
private AVLNode<K, V> left, right, parent;
private int height = 1;
private K key;
private V value;
public AVLNode() {}
public AVLNode(K key, V value) {
this.key = key;
this.value = value;
}
public V getValue() {
return value;
}
public K getKey() {
return key;
}
}
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我究竟做错了什么?
AVLNode是通用的,用K和参数化V.在你的Comparator<AVLNode>,AVLNode是生的.那是,K而且V不为人知.这意味着编译器居然不知道,如果K是Comparable.
尝试制作它Comparator<AVLNode<String, ?>>.
不相关,但也使用new AVLNode<>(...).
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