我正在制作一个应用程序来测试你的政治或天文学.
我的问题是,当你说"政治"或你说"天文学"时,在给出所需的"测试"输出之前,它会再次要求你2次输入.
这是代码:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
do {
if (getAnswer().equalsIgnoreCase("neither")) {
System.out.println("Please enter \'astronomy\' or \'politics\'.");
}
getAnswer();
}
while(getAnswer().equalsIgnoreCase("neither"));
System.out.println("test");
}
public static String getAnswer() {
Scanner quizType = new Scanner(System.in);
System.out.println("Would you like to be quizzed on politics or astronomy?");
String typeAnswer = quizType.next();
if (typeAnswer.equalsIgnoreCase("politics")) {
return "politics";
}
else if (typeAnswer.equalsIgnoreCase("astronomy")) {
return "astronomy";
}
else {
return "neither";
}
}
}
Run Code Online (Sandbox Code Playgroud)
有任何想法吗?
谢谢
有没有必要 getAnswer() 3次,只是getAnswer()到一个String变量,你是好去.
像这样:
public static void main(String[] args) {
String answer = "";
do {
answer = getAnswer();
if (answer.equalsIgnoreCase("neither")) {
System.out.println("Please enter \'astronomy\' or \'politics\'.");
}
} while (answer.equalsIgnoreCase("neither"));
System.out.println("test");
}
public static String getAnswer() {
Scanner quizType = new Scanner(System.in);
System.out.println("Would you like to be quizzed on politics or astronomy?");
String typeAnswer = quizType.next();
if (typeAnswer.equalsIgnoreCase("politics")) {
return "politics";
} else if (typeAnswer.equalsIgnoreCase("astronomy")) {
return "astronomy";
} else {
return "neither";
}
}
Run Code Online (Sandbox Code Playgroud)