如何在URL中重命名REST路由？

Question

给我一个名为的模型Apple并且它有一个控制器ApplesController,路由是:

resources :apples

    apples  GET    /apples (.:format)          {:controller=>"apples ", :action=>"index"}
  new_apple GET    /apples /new(.:format)      {:controller=>"apples ", :action=>"new"}
 edit_apple GET    /apples /:id/edit(.:format) {:controller=>"apples ", :action=>"edit"}

我想保持所有代码相同,除了在URL中,"apple"将被"car"替换.因此,URL /apples/new将成为/cars/new.

有没有办法在不触及应用程序中的任何其他代码的情况下执行此操作？(即在应用内部,它仍然apple和ApplesController)

我尝试过:as选项:

resources :apples, :as => "cars"

    cars    GET    /apples (.:format)          {:controller=>"apples ", :action=>"index"}
  new_car   GET    /apples /new(.:format)      {:controller=>"apples ", :action=>"new"}
 edit_car   GET    /apples /:id/edit(.:format) {:controller=>"apples ", :action=>"edit"}

但这只改变了路线的"名称",而不是URL(所以new_apple_path变成了new_car_path,但new_car_path仍然指向/apples/new而不是/cars/new)

Answer 1

你想要做的是传递:path选项

resources :apples, :path => "cars"

这将用/applesto 替换所有路由引用/cars

请参阅:http://guides.rubyonrails.org/routing.html,第4.7节"翻译路径"