具有变量值的Django查询集

İlk*_*aya 5 python django variables django-queryset

我正在 django 中为我的数据库编写动态过滤器,我在其中使用以下代码,其中有 2 个变量(p_type,s_type):

        p_type=[]
        s_type=[]
        query = request.GET.get("q")
        p_type =request.GET.get("p_type")
        s_type = request.GET.get("s_type")
        #messages.add_message(request, messages.INFO, p_type)
        #messages.add_message(request, messages.INFO, s_type)
        if query:
            queryset_find = queryset_list.filter(
                Q(FP_Item__contains=query))
            context = {'object_list': queryset_find}
            return render(request, 'index.html', context)
        elif p_type:
            queryset_find = queryset_list.filter(
                Q(p_type__contains=s_type))
            context = {'object_list': queryset_find}
            return render(request, 'index.html', context)
        else:
            context = {'object_list': queryset}
            return render(request, 'index.html', context)
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但是 django 在下面一行返回错误

Q(p_type__contains=s_type))
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我有动态单选按钮,其中 p_type 的值与我的数据库匹配,但即使我收到以下错误:

Exception Type: FieldError
Exception Value:    
Cannot resolve keyword 'p_type' into field. Choices are: ... (same choices which I am using with my database).
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变量查询不可行吗?还有其他方法吗?

模型:

class RFP(models.Model):
    FP_Item = models.TextField(max_length=1500)
    P_63 = models.TextField(max_length=1000)
    P_64 = models.TextField(max_length=1000)
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Wil*_*ing 4

如果p_type保存了您要查询的字段名称,那么您可以执行以下操作:

elif p_type:
    kwargs = {
        '{}__contains'.format(p_type): s_type
    }
    queryset_find = queryset_list.filter(Q(**kwargs))
    ...
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