Swift 4中的UIButton数组

Question

我已经使用UIButtons在UiKit中制作了一系列复选框：

@IBOutlet weak var Box1: UIButton!
@IBOutlet weak var Box2: UIButton!
@IBOutlet weak var Box3: UIButton!
....
@IBOutlet weak var Box59: UIButton!




// Gives the button an action
@IBAction func Box1(_ sender: UIButton) {
    sender.isSelected = !sender.isSelected
}
@IBAction func Box2(_ sender: UIButton) {
    sender.isSelected = !sender.isSelected
}
@IBAction func Box3(_ sender: UIButton) {
    sender.isSelected = !sender.isSelected
}
    ....
@IBAction func Box59(_ sender: UIButton) {
    sender.isSelected = !sender.isSelected
}




// Creates button images of checkbox and unchecked box
var BoxON = UIImage(named: "CheckBox")
var BoxOFF = UIImage(named:"UnCheckBox")




// Allows the button to be set to the image, if selected or not 
override func viewDidAppear(_ animated: Bool) {
    super.viewDidAppear(animated)

    Box1.setImage(BoxOFF, for: .normal)
    Box1.setImage(BoxON, for: .selected)

    Box2.setImage(BoxOFF, for: .normal)
    Box2.setImage(BoxON, for: .selected)

    Box3.setImage(BoxOFF, for: .normal)
    Box3.setImage(BoxON, for: .selected)
    ....
    Box59.setImage(BoxOFF, for: .normal)
    Box59.setImage(BoxON, for: .selected)

    }

这是制作尽可能多的复选框所必需的所有代码。但是，每个复选框都需要在故事板上的正确位置创建/移动按钮，并将按钮从故事板上链接到刚刚编码的按钮变量。这可能会花费很多时间，因为每个视图控制器需要100多个按钮。

是否有通过制作按钮数组来实现此目的的更快方法？或类似的东西？

Answer 1

可以声明一个IBOutletas数组

• 创建一个IBOutletas数组

  @IBOutlet var boxes : [UIButton]!
  

• 将所有按钮连接到同一插座（按所需顺序）

• 在viewDidAppear使用循环或forEach

  override func viewDidAppear(_ animated: Bool) {
      super.viewDidAppear(animated)
  
      boxes.forEach {
          $0.setImage(BoxOFF, for: .normal)
          $0.setImage(BoxON, for: .selected)
      }
  }
  

• 向按钮添加唯一标签（可选）。

• 创建一个IBAction并将所有按钮连接到动作

• 使用switch语句通过数组中的索引或标签来区分按钮

  @IBAction func boxTouched(_ sender: UIButton) {
      sender.isSelected = !sender.isSelected
      let index = boxes.index(of: sender)!
      switch index {
         // handle the cases
      }
  }
  
  @IBAction func boxTouched(_ sender: UIButton) {
      sender.isSelected = !sender.isSelected
      switch sender.tag {
         // handle the cases
      }
  }