使API通过Async / Await获取“ POST”的正确方法

Question

我正在做一个需要我向API发出请求的项目。用Async / Await发出POST请求的正确形式是什么？

举例来说，这是我获取所有设备列表的方法。如何将请求更改为POST以创建新设备？我知道我必须添加带有数据主体的标头。

getDevices = async () => {
  const location = window.location.hostname;
  const response = await fetch(
    `http://${location}:9000/api/sensors/`
  );
  const data = await response.json();
  if (response.status !== 200) throw Error(data.message);
  return data;
};

Answer 1

2021 答案：以防万一您在这里寻找如何使用 async/await 或 Promise 与 axios 相比进行 GET 和 POST Fetch api 请求。

我正在使用 jsonplaceholder fake API 来演示：

使用 async/await 获取 api GET 请求：

         const asyncGetCall = async () => {
            try {
                const response = await fetch('https://jsonplaceholder.typicode.com/posts');
                 const data = await response.json();
                // enter you logic when the fetch is successful
                 console.log(data);
               } catch(error) {
            // enter your logic for when there is an error (ex. error toast)
                  console.log(error)
                 } 
            }


          asyncGetCall()

使用 async/await 获取 api POST 请求：

    const asyncPostCall = async () => {
            try {
                const response = await fetch('https://jsonplaceholder.typicode.com/posts', {
                 method: 'POST',
                 headers: {
                   'Content-Type': 'application/json'
                   },
                   body: JSON.stringify({
             // your expected POST request payload goes here
                     title: "My post title",
                     body: "My post content."
                    })
                 });
                 const data = await response.json();
              // enter you logic when the fetch is successful
                 console.log(data);
               } catch(error) {
             // enter your logic for when there is an error (ex. error toast)

                  console.log(error)
                 } 
            }

asyncPostCall()

使用 Promise 的 GET 请求：

  fetch('https://jsonplaceholder.typicode.com/posts')
  .then(res => res.json())
  .then(data => {
   // enter you logic when the fetch is successful
    console.log(data)
  })
  .catch(error => {
    // enter your logic for when there is an error (ex. error toast)
   console.log(error)
  })

使用 Promise 的 POST 请求：

fetch('https://jsonplaceholder.typicode.com/posts', {
  method: 'POST',
  headers: {
    'Content-Type': 'application/json',
  },
   body: JSON.stringify({
     // your expected POST request payload goes here
      title: "My post title",
      body: "My post content."
      })
})
  .then(res => res.json())
  .then(data => {
   // enter you logic when the fetch is successful
    console.log(data)
  })
  .catch(error => {
  // enter your logic for when there is an error (ex. error toast)
   console.log(error)
  })  

使用 Axios 获取请求：

        const axiosGetCall = async () => {
            try {
              const { data } = await axios.get('https://jsonplaceholder.typicode.com/posts')
    // enter you logic when the fetch is successful
              console.log(`data: `, data)
           
            } catch (error) {
    // enter your logic for when there is an error (ex. error toast)
              console.log(`error: `, error)
            }
          }
    
    axiosGetCall()

使用 Axios 的 POST 请求：

const axiosPostCall = async () => {
    try {
      const { data } = await axios.post('https://jsonplaceholder.typicode.com/posts',  {
      // your expected POST request payload goes here
      title: "My post title",
      body: "My post content."
      })
   // enter you logic when the fetch is successful
      console.log(`data: `, data)
   
    } catch (error) {
  // enter your logic for when there is an error (ex. error toast)
      console.log(`error: `, error)
    }
  }


axiosPostCall()

Answer 2

实际上，您的代码可以像这样进行改进：

要发表文章，只需在获取调用的设置上添加方法。

getDevices = async () => {
    const location = window.location.hostname;
    const settings = {
        method: 'POST',
        headers: {
            Accept: 'application/json',
            'Content-Type': 'application/json',
        }
    };
    try {
        const fetchResponse = await fetch(`http://${location}:9000/api/sensors/`, settings);
        const data = await fetchResponse.json();
        return data;
    } catch (e) {
        return e;
    }    

}

Answer 3

这是配置示例：

try {
    const config = {
        method: 'POST',
        headers: {
            'Accept': 'application/json',
            'Content-Type': 'application/json',
        },
        body: JSON.stringify(data)
    }
    const response = await fetch(url, config)
    //const json = await response.json()
    if (response.ok) {
        //return json
        return response
    } else {
        //
    }
} catch (error) {
        //
}