如何获取使用 Angular5 下载的文件的名称

Question

我的回复标题是：

HTTP/1.1 200 OK
Content-Disposition: attachment; filename="file.docx"
Accept-Ranges: bytes
Cache-Control: public, max-age=0
Last-Modified: Thu, 26 Apr 2018 10:37:00 GMT
ETag: W/"c61-16301871843"
Content-Type: application/vnd.openxmlformats-officedocument.wordprocessingml.document
Content-Length: 3169
Date: Thu, 26 Apr 2018 10:37:00 GMT
Connection: keep-alive

我试过这段代码，

 public download(id: string): Observable<Blob> {
    let headers = new Headers();
    const _baseUrl = (Api.getUrl(Api.URLS.download));
    headers.append('x-access-token', this.auth.getCurrentUser().token);
    headers.append('sale_id', id);
    return this.http.get(_baseUrl, { headers: headers, responseType: ResponseContentType.Blob})
      .map((res) => {
        console.log(res.headers) // show like in image
        return new Blob([res.blob()], { type: 'application/octet-stream' })
      });
  }

在控制台中显示：

没有显示内容处置！

如何从标题中获取文件名？

Answer 1

希望这能节省您的时间

首先将 file-saver 导入到 elements.ts 文件中

import { saveAs } from 'file-saver';

return this.http.get(url, { headers: {
  Accept: 'application/json',
  'Content-Type': 'application/json',
}, responseType: 'blob', observe: 'response' })
  .pipe().subscribe({
    next: (response: any) => {
      let fileName = 'file';
      const contentDisposition = response.headers.get('Content-Disposition');
      if (contentDisposition) {
        const fileNameRegex = /filename[^;=\n]*=((['"]).*?\2|[^;\n]*)/;
        const matches = fileNameRegex.exec(contentDisposition);
        if (matches != null && matches[1]) {
          fileName = matches[1].replace(/['"]/g, '');
        }
      }
      const fileContent = response.body;
      const blob = new Blob([fileContent], { type: 'application/octet-stream' });
      saveAs(blob, fileName);
    },
    error: (error) => {
      this.handleError(error);
    }
  });

另外，设置 API 侧标头，例如

'Access-Control-Expose-Headers', 'Content-Disposition'