Jep*_*sen 3 c# xaml xamarin xamarin.forms
我创建了一个从SQLite DB填充的列表视图.XML看起来像这样:
<ListView x:Name="CalculationListview" ItemsSource="{Binding Calculation}" HasUnevenRows="true">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout>
<Label Text="{Binding Qty}"></Label>
<Label Text="{Binding Note}"></Label>
<Button Text="Delete" Clicked="Handle_Clicked"></Button>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Run Code Online (Sandbox Code Playgroud)
我已经创建了一个按钮,如果单击该按钮,我想从中删除该项目.
我已经从数据库中删除了一个接收给定对象的方法.
public Task<int> DeleteCalculationAsync(Calculation calculation)
{
return database.DeleteAsync(calculation);
}
Run Code Online (Sandbox Code Playgroud)
不幸的是,我不知道如何从bindingcontext中获取对象,以便我可以删除该项目.我显然已经点击了事件处理程序:
void Handle_Clicked(object sender, System.EventArgs e)
{
App.Database.DeleteCalculationAsync(SOMETHING HERE);
}
Run Code Online (Sandbox Code Playgroud)
我建议将删除功能移到Context Actions.
当用户长按ViewCell时,当用户在ViewCell上从右向左滑动时,上下文操作将出现在iOS上.
此屏幕截图来自Xamarin.Forms文档,并未反映下面的代码.

<ListView x:Name="CalculationListview" ItemsSource="{Binding Calculation}" HasUnevenRows="true">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<ViewCell.ContextActions>
<MenuItem Text="Delete" IsDestructive="True" Clicked="Handle_Delete"/>
</ViewCell.ContextActions>
<StackLayout>
<Label Text="{Binding Qty}"></Label>
<Label Text="{Binding Note}"></Label>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Run Code Online (Sandbox Code Playgroud)
async void Handle_Delete(object sender, System.EventArgs e)
{
var viewCellSelected = sender as MenuItem;
var calculationToDelete = viewCellSelected?.BindingContext as Calculation;
await App.Database.DeleteCalculationAsync(calculationToDelete);
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
564 次 |
| 最近记录: |