Mat*_*ara 1 javascript java jquery spring spring-boot
当我向我的网址发送帖子请求时,我的控制器设法将记录保存到数据库,但我的ajax出错了.我究竟做错了什么?我的js代码:
function salvarValores(){
capturarValores()
$.ajax({
type: "POST",
url: "/service/newService/service",
dataType: "json",
contentType: 'application/json',
data: JSON.stringify(( { 'cpfPessoa': cpfCliente, "descricaoServico": descricao } )),
success: function(data){
alert("Record successfully entered");
location.reload();
},
error: function(data){
alert("Error performing operation");
location.reload();
}
});
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}
我的春季启动控制器
@PostMapping("/service/newService/service")
@ResponseBody
public ResponseEntity<String> newService(@RequestBody Service service) {
if (serviceDao.addObject(service)) {
logger.debug("Adding data");
return new ResponseEntity<String>("Data successfully saved", HttpStatus.OK);
}
logger.error("Error to insert data in database");
return new ResponseEntity<String>("Error to insert data in database", HttpStatus.FAILED_DEPENDENCY);
}
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当我单击保存按钮时,我有一条警告,其中显示"错误执行操作"但该记录已正确插入数据库
你已经告诉jQuery你期待JSON回来了:
$.ajax({
// ...
dataType: "json", // <== Here
// ...
});
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...但你返回的不是JSON:
return new ResponseEntity<String>("Data successfully saved", HttpStatus.OK);
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因此,当jQuery尝试为您解析响应(作为JSON)时,它会失败.
删除dataType参数(或将其设置为"text").更多文档.
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