Qwe*_*tiy 5 javascript svg node.js snap.svg
我需要相交 2 条 SVG 路径并获得与它们相交的路径。
它应该在浏览器或 Node.js 中工作(它们中的任何一个,而不是两者)。
我需要交集,使用的clip-path不行。
如果由于某种原因交集会使用transform它就可以了(我会自己删除它)。
我认为有一个图书馆,但我发现只有
path例如交叉以下路径:
M 24.379464,51.504463 23.434524,23.156249 38.742559,12.572916 c 0,0 29.860118,-9.0714281 17.00893,0.755953 -12.851191,9.82738 13.229166,19.465774 13.229166,19.465774 z
m 32.883928,0.28869028 c 0,0 -15.686011,1.51190452 -8.504463,7.18154712 7.181546,5.6696426 50.270836,30.0491076 26.458332,42.3333336 -23.8125,12.284226 47.058036,14.174107 47.058036,14.174107 z
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我想得到类似的东西:
M 43.943359 11.123047 C 40.995759 11.900151 38.742188 12.572266 38.742188 12.572266 L 35.236328 14.996094 C 44.091432999999995 21.21816 55.052161 29.822765 57.455078 37.628906 L 66.939453 33.650391 63.632812 30.410156 C 58.77426 27.95814 52.364322 23.85552 52.214844 19.224609 L 43.943359 11.123047 z
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这是path示例中带有s 的交互式片段(忽略颜色 - 它们是为了清楚起见) - 需要Intersection从#path1和获取#path2:
M 24.379464,51.504463 23.434524,23.156249 38.742559,12.572916 c 0,0 29.860118,-9.0714281 17.00893,0.755953 -12.851191,9.82738 13.229166,19.465774 13.229166,19.465774 z
m 32.883928,0.28869028 c 0,0 -15.686011,1.51190452 -8.504463,7.18154712 7.181546,5.6696426 50.270836,30.0491076 26.458332,42.3333336 -23.8125,12.284226 47.058036,14.174107 47.058036,14.174107 z
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M 43.943359 11.123047 C 40.995759 11.900151 38.742188 12.572266 38.742188 12.572266 L 35.236328 14.996094 C 44.091432999999995 21.21816 55.052161 29.822765 57.455078 37.628906 L 66.939453 33.650391 63.632812 30.410156 C 58.77426 27.95814 52.364322 23.85552 52.214844 19.224609 L 43.943359 11.123047 z
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使用 Snap.svg 的示例:
svg { width: 10em; width: 100vmin; outline: 1px dotted blue; display: none; }
input { display: none; }
label { width: 10em; float: left; clear: left; cursor: pointer; line-height: 2em; margin: 0 .5em .25em 0; padding: 0 .25em; border: 1px solid; }
:checked + * + * + label { background: antiquewhite; color: blue; }
:checked + * + * + * + * + * + svg { display: inline-block; }Run Code Online (Sandbox Code Playgroud)
<input type=radio name=svg id=in checked>
<input type=radio name=svg id=out>
<input type=radio name=svg id=cp>
<label for=in>Input</label>
<label for=out>Intersection</label>
<label for=cp>Clip</label>
<svg xmlns:svg="http://www.w3.org/2000/svg" xmlns="http://www.w3.org/2000/svg" viewBox="22 0 76 64">
<path id="path1"
style="fill:rgba(255,0,0,.5); stroke:red;stroke-width:0.26458332px;"
d="M 24.379464,51.504463 23.434524,23.156249 38.742559,12.572916 c 0,0 29.860118,-9.0714281 17.00893,0.755953 -12.851191,9.82738 13.229166,19.465774 13.229166,19.465774 z"
/>
<path id="path2"
style="fill:rgba(0,255,0,.5);stroke:green;stroke-width:0.26458332px;"
d="m 32.883928,0.28869028 c 0,0 -15.686011,1.51190452 -8.504463,7.18154712 7.181546,5.6696426 50.270836,30.0491076 26.458332,42.3333336 -23.8125,12.284226 47.058036,14.174107 47.058036,14.174107 z"
/>
</svg>
<svg xmlns:svg="http://www.w3.org/2000/svg" xmlns="http://www.w3.org/2000/svg" viewBox="22 0 76 64">
<path
style="fill:rgba(0,0,255,.5);stroke:blue;stroke-width:0.26458332px;"
d="M 43.943359 11.123047 C 40.995759 11.900151 38.742188 12.572266 38.742188 12.572266 L 35.236328 14.996094 C 44.091432999999995 21.21816 55.052161 29.822765 57.455078 37.628906 L 66.939453 33.650391 63.632812 30.410156 C 58.77426 27.95814 52.364322 23.85552 52.214844 19.224609 L 43.943359 11.123047 z"
/>
</svg>
<svg xmlns:svg="http://www.w3.org/2000/svg" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="22 0 76 64">
<clipPath id="clip2">
<use xlink:href="#path2" />
</clipPath>
<use xlink:href="#path1" clip-path="url(#clip2)" />
</svg>Run Code Online (Sandbox Code Playgroud)
var p1 = "M 24.379464,51.504463 23.434524,23.156249 38.742559,12.572916 c 0,0 29.860118,-9.0714281 17.00893,0.755953 -12.851191,9.82738 13.229166,19.465774 13.229166,19.465774 z"
var p2 = "m 32.883928,0.28869028 c 0,0 -15.686011,1.51190452 -8.504463,7.18154712 7.181546,5.6696426 50.270836,30.0491076 26.458332,42.3333336 -23.8125,12.284226 47.058036,14.174107 47.058036,14.174107 z"
var intersection = Snap.path.intersection(p1, p2)
console.log(intersection)Run Code Online (Sandbox Code Playgroud)
PS:同样的问题俄语。
我们可以使用 PaperJS 布尔运算来实现,它可以对 SVG 路径进行运算。
PaperJS 有 5 种不同的布尔运算:exclude、subtract、unite、intersect,divide我们将使用其中一个名称为 的布尔运算intersect。这些操作也是同名的函数,它们返回item具有函数 的对象exportSVG()。它返回 true SVG Path element,它具有两条路径交叉点的新形状。
正确解决方案示例
paper.install(window);
window.onload = function()
{
paper.setup('canvas');
var p1 = 'M 24.379464,51.504463 23.434524,23.156249 38.742559,12.572916 c 0,0 29.860118,-9.0714281 17.00893,0.755953 -12.851191,9.82738 13.229166,19.465774 13.229166,19.465774 z',
p2 = 'm 32.883928,0.28869028 c 0,0 -15.686011,1.51190452 -8.504463,7.18154712 7.181546,5.6696426 50.270836,30.0491076 26.458332,42.3333336 -23.8125,12.284226 47.058036,14.174107 47.058036,14.174107 z',
path1 = new Path(p1),
path2 = new Path(p2);
path1.fillColor = 'rgba(255,0,0,.5)';
path1.position = new Point(25, 25);
path2.fillColor = 'rgba(0,255,0,.5)';
path2.position = new Point(40, 25);
var result = path2.intersect(path1);
result.selected = true;
result.fillColor = '#77f';
//exportSVG() docu: http://paperjs.org/reference/item/#exportsvg
var svgPathElement = result.exportSVG(),
dPath = svgPathElement.getAttribute('d');
document.querySelector('path').setAttribute('d', dPath);
var output = document.querySelector('#output');
output.innerHTML = '<pre>' + dPath + '</pre>';
output.innerHTML += '<xmp>' + svgPathElement.outerHTML + '</xmp>';
};Run Code Online (Sandbox Code Playgroud)
table
{
margin-left:14px;
padding-left:14px;
border-left:1px solid gray;
display:inline-block
}Run Code Online (Sandbox Code Playgroud)
<script src="https://cdnjs.cloudflare.com/ajax/libs/paper.js/0.12.0/paper-full.min.js"></script>
<canvas id="canvas" width="75" height="75" resize></canvas>
<table><tr><td><b>Our new shape of both paths intersection in separate SVG:</b></td></tr>
<tr><td>
<svg width="75" height="75" viewBox="0 0 75 75">
<path fill="rgba(0,0,255,.5)" d=""/>
</svg>
</td></tr></table>
<div id="output"></div>Run Code Online (Sandbox Code Playgroud)
有用的链接:
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