使用ASP或PHP检查2个目录中是否存在文件

Question

我正在寻找一种方法来比较2个目录,看看两个文件是否存在.我想要做的是删除其中一个目录中的文件(如果两个目录中都存在).

我可以使用ASP或PHP.

例:

/devices/1001
/devices/1002
/devices/1003
/devices/1004
/devices/1005

/disabled/1001
/disabled/1002
/disabled/1003

因此,由于1001, 1002, 1003存在/ disabled /,我想从/ devices /中删除它们,只留1004, 1005在/ devices /中.

Answer 1

使用scandir()来获取文件名的每个目录的数组,然后使用array_intersect()发现,存在于任何给定其他参数的第一个数组的元素.

http://au.php.net/manual/en/function.scandir.php

http://au.php.net/manual/en/function.array-intersect.php

<?php
$devices = scandir('/i/auth/devices/');
$disabled = scandir('/i/auth/disabled/');

foreach(array_intersect($devices, $disabled) as $file) {
    if ($file == '.' || $file == '..')
        continue;
    unlink('/i/auth/devices/'.$file);
}

应用为包括检查目录有效的功能:

<?php
function removeDuplicateFiles($removeFrom, $compareTo) {
    $removeFromDir = realpath($removeFrom);
    if ($removeFromDir === false)
        die("Invalid remove from directory: $removeFrom");

    $compareToDir = realpath($compareTo);
    if ($compareToDir === false)
        die("Invalid compare to directory: $compareTo");

    $devices = scandir($removeFromDir);
    $disabled = scandir($compareToDir);

    foreach(array_intersect($devices, $disabled) as $file) {
        if ($file == '.' || $file == '..')
            continue;
        unlink($removeFromDir.DIRECTORY_SEPARATOR.$file);
    }
}

removeDuplicateFiles('/i/auth/devices/', '/i/auth/disabled/');