如何获取具有给定类型的类实例的所有成员？

Question

我有一个类似的课程

public class Stuff
    {
        public int A;
        public float B;
        public int C;
        public float D;
        public int E;

        public List<float> AllMyFloats { get {/* how to grab B, D,... into new List<float>? */} }
     }

如何获取一种类型的所有内容(比如float在给定的样本中)并在属性访问时返回它们？

Answer 1

反思是你的朋友.

public class Stuff
{
    public int A { get; set; }
    public float B { get; set; }
    public int C { get; set; }
    public float D { get; set; }
    public int E { get; set; }

    public List<float> GetAllFloats()
    {
        var floatFields = GetType().GetProperties()
          .Where(p => p.PropertyType == typeof(float));
        return floatFields.Select(p => (float)p.GetValue(this)).ToList();
    }
}

class Program
{   
    static void Main()
    {
        Stuff obj = new Stuff() { A = 1, B = 2, C = 3, D = 4, E = 5 };
        obj.GetAllFloats().ForEach(f => Console.WriteLine(f));
        Console.ReadKey();
    }
}

输出:

2
4