在 PHP 中使用 Google 语音识别 API

Question

我想制作一个使用谷歌语音识别的简单脚本，我尝试了各种方法，以便我可以使用请求正文访问API，但总是失败。

示例网址：https : //content-speech.googleapis.com/v1/speech : recognize?prettyPrint=true&alt=json&key=AIzaSyD-XXXXXXXXXXXXXXXXXX-Al7hLQDbugrDcw

JSON 示例：

{
"audio": {
    "content": "ZkxhQwAAACIEg....more......FzSi6SngVApeE="
  },
  "config": {
    "encoding": "FLAC",
    "sampleRateHertz": 16000,
    "languageCode": "en-US"
  }
}

Answer 1

文档：https : //cloud.google.com/speech-to-text/docs/basics

代码示例：https : //cloud.google.com/speech-to-text/docs/samples

考虑使用库：

谷歌云客户端库 PHP（也有代码示例）：https : //googlecloudplatform.github.io/google-cloud-php/#/docs/google-cloud/v0.61.0/speech/speechclient

Speech-to-Text 客户端库 https://cloud.google.com/speech-to-text/docs/reference/libraries#client-libraries-install-php

扬声器是您可以使用的 3.party 库：https : //github.com/duncan3dc/speaker

来自 google/cloud-speech 的快速示例：

安装：

composer require google/cloud-speech

样本：

  # Includes the autoloader for libraries installed with composer
require __DIR__ . '/vendor/autoload.php';

# Imports the Google Cloud client library
use Google\Cloud\Speech\SpeechClient;

# Your Google Cloud Platform project ID
$projectId = 'YOUR_PROJECT_ID';

# Instantiates a client
$speech = new SpeechClient([
    'projectId' => $projectId,
    'languageCode' => 'en-US',
]);

# The name of the audio file to transcribe
$fileName = __DIR__ . '/resources/audio.raw';

# The audio file's encoding and sample rate
$options = [
    'encoding' => 'LINEAR16',
    'sampleRateHertz' => 16000,
];

# Detects speech in the audio file
$results = $speech->recognize(fopen($fileName, 'r'), $options);

foreach ($results as $result) {
    echo 'Transcription: ' . $result->alternatives()[0]['transcript'] . PHP_EOL;
}