nik*_*nik 1 java date weekday date-difference
我试图找到两个日期之间的工作日计数(周末和时间必须忽略).我正在使用以下功能来做到这一点.但它给出了多种情况的错误结果,例如,如果startdate是周末还是enddate是周末.这是一个演示的例子,可以计算一天额外的一天.
2018-03-08 00:00:00.0和2018-04-22 01:37:29.887
计数返回32(应该是31,它也在考虑23-04-2018).请提供一些完美的解决方案/方法来做同样的事情.
private static int calculateDuration(Date startDate, Date endDate)
{
Calendar startCal = Calendar.getInstance();
startCal.setTime(startDate);
startCal.set( Calendar.HOUR_OF_DAY, 0 );
startCal.set( Calendar.MINUTE, 0 );
startCal.set( Calendar.SECOND, 0 );
startCal.set( Calendar.MILLISECOND, 0 );
Calendar endCal = Calendar.getInstance();
endCal.setTime(endDate);
endCal.set( Calendar.HOUR_OF_DAY, 0 );
endCal.set( Calendar.MINUTE, 0 );
endCal.set( Calendar.SECOND, 0 );
endCal.set( Calendar.MILLISECOND, 0 );
int workDays = 0;
if (startCal.getTimeInMillis() > endCal.getTimeInMillis())
{
startCal.setTime(endDate);
endCal.setTime(startDate);
}
do
{
startCal.add(Calendar.DAY_OF_MONTH, 1);
System.out.println("************"+Calendar.DAY_OF_WEEK);
System.out.println("Before weekend condition"+Calendar.DAY_OF_WEEK+"Workdays="+workDays);
if (startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY && startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY)
{
workDays++;
System.out.println("This day picked "+startCal.getTime()+"Workdays="+workDays);
}
}
while (startCal.getTimeInMillis() <= endCal.getTimeInMillis());
System.out.println("Final workdays count for "+startDate+" and "+endDate+" is"+workDays);
return workDays;
}
Run Code Online (Sandbox Code Playgroud)
我尝试了多种解决方案,但除了上面提到的场景外,这种方
我强烈建议使用java.time.LocalDate::datesUntilJava 9及更高版本中的方法.它只需要几行来计算,而不必使用Calendar:
var startDate = LocalDate.parse("2018-03-08");
var endDate = LocalDate.parse("2018-04-22");
var numWeekDays = startDate.datesUntil(endDate)
.map(LocalDate::getDayOfWeek)
.filter(d -> d != DayOfWeek.SATURDAY && d != DayOfWeek.SUNDAY)
.count();
System.out.println(numWeekDays);
Run Code Online (Sandbox Code Playgroud)
输出:
32
Run Code Online (Sandbox Code Playgroud)