T-SQL函数用于获取存储的字符的ASCII值

Question

我正在使用T-SQL块来获取存储在数据库列中的ascii字符的转储.我知道这可以在Oracle中使用DUMP()函数轻松完成.我不熟悉SQL Server sytax,但我使用的是这样的东西.

    SET NOCOUNT ON
-- Create the variables for the current character string position 
-- and for the character string.
DECLARE @position int, @string char(15), @output char(1000), @output2 char(2000)
-- Initialize the variables.
SET @position = 1
SET @output2 = 'Start:'
SELECT @string = name from 
location where location_type = 4405 and owner_id = 362
and location_id = 53183
WHILE @position <= DATALENGTH(@string)

       BEGIN
       SELECT @output = CAST(ASCII(SUBSTRING(@string, @position, 1)) AS CHAR)
        + ' ' +      CHAR(ASCII(SUBSTRING(@string, @position, 1)))
        PRINT @output
        --SET @output2 = @output2 + '=' + @output
        SET @position = @position + 1
       END
        --PRINT @output2 
    SET NOCOUNT OFF
    GO

出于某种原因,如果我取消注释与@ output2相关的代码,它将无法正确打印@ output2.我们的想法是将所有ascii值作为单行返回,而不是为每个字符获取一行.难道我做错了什么？

Answer 1

如果你正在寻找一排,这可能是最容易的方式(建立在Cyber​​kiwi的答案上)

DECLARE @string char(15),
@output1 varchar(1000),
@output2 varchar(1000)

SELECT @string = name
from  location
where location_type = 4405 and owner_id = 362
and location_id = 53183

SET @output1 = ''
SET @output2 = ''

select 
    @output1 = @output1 + SUBSTRING(@string, number, 1) + ', ', 
    @output2 = @output2 + cast(ASCII(SUBSTRING(@string, number, 1)) as varchar) + ', '
from master..spt_values
where type='p' and number between 1 and LEN(@string)
order by number

PRINT @output1
PRINT @output2