复制curl在Python中协商连接(使用kerberos auth)

Question

我想在Python中复制以下curl命令.

curl -u : --negotiate -k https://example.com/authenticate

我在这里跟踪了这个pycurl示例,它运行良好 http://www.deplication.net/2014/02/curl-with-kerberos-authentication.html

curl = pycurl.Curl()
curl.setopt(pycurl.HTTPAUTH, pycurl.HTTPAUTH_GSSNEGOTIATE)
curl.setopt(pycurl.USERPWD, ':')
curl.setopt(pycurl.URL, 'https://example.com/authenticate'
curl.perform()

有没有办法用Python请求模块做到这一点？

谢谢!!

Answer 1

您可以尝试此项目： https: //pypi.org/project/requests-negotiate/，或者如果您使用 Kerberos：https://pypi.org/project/requests-kerberos/

无论使用哪种方式，您的代码都将如下所示：

auth = HTTPNegotiateAuth()  # or: HTTPKerberosAuth()
response = requests.get('https://example.com/authenticate', auth=auth, verify=False)