从PHP上的多维数组中获取数组值数组

Question

我得到了什么.

这是我从我的表单中获得的数组形式多个复选框.

$test1 = array(
    '0' => 'test1',
    '1' => 'test2',
    '2' => 'test3'  
);


$test2 = array(
    '0' => 'test21',
    '1' => 'test22',
    '2' => 'test23' 
);


$test3 = array(
    '0' => 'test31',
    '1' => 'test32',
    '2' => 'test33' 
);


$test4 = array(
    '0' => 'test41',
    '1' => 'test42',
    '2' => 'test43' 
);

我需要将此数组转换为如下所示:

结果需要.

$result_needed = [ 

    '0' => ['0' => 'test1', '1' => 'test21', '2' => 'test31', '3' => 'test41'],
    '1' => ['0' => 'test2', '1' => 'test22', '2' => 'test32', '3' => 'test42'],
AND SO ON....
];

到目前为止我尝试了什么？

我试图将每个数组添加到最终数组中,然后在其上使用foreach循环它得到结果,但它没有帮助.这是我试过的.

$final = ['test1' => $test1, 'test2' => $test2, 'test3' => $test3, 'test4' => $test4];


echo "<pre>";

$step1 = array();

foreach($final as $key => $val){

    $step1[$key] = $val;    

}

print_r($step1);

Answer 1

您可以使用循环并推送到结果数组

$final = ['test1' => $test1, 'test2' => $test2, 'test3' => $test3, 'test4' => $test4];

$step1 = [];
foreach ($final as $tests) {
    foreach ($tests as $key => $value) {
        if (!array_key_exists($key, $step1)) {
            $step1[$key] = [];
        }

        $step1[$key][] = $value;
    }
}

print_r($step1);