检查所有鼠标按钮的按钮状态

Question

是否有更好的方法来检查所有鼠标按钮的按钮状态,而不是检查任何不同的按钮额外？

var mouseEventArgs = (System.Windows.Input.MouseEventArgs)e.StagingItem.Input;

if (mouseEventArgs.LeftButton == MouseButtonState.Released &&
    mouseEventArgs.MiddleButton == MouseButtonState.Released &&
    mouseEventArgs.RightButton == MouseButtonState.Released &&
    mouseEventArgs.XButton1 == MouseButtonState.Released &&
    mouseEventArgs.XButton2 == MouseButtonState.Released)
{
    return;
}

如果没有,如果不重复自己,我怎么能更优雅呢？

提前致谢!

Answer 1

我不认为除了将其重构为方法之外你还能做很多事情,因为所有按钮都没有预定义的集合.如果您希望它完全看不见,您可以使用这样的扩展方法:

public static class Extensions
{
    public static bool CheckUniformButtonState(this MouseButtonEventArgs e, MouseButtonState state)
    {
        switch (state)
        {
            case MouseButtonState.Pressed:
                return (e.LeftButton == MouseButtonState.Pressed &&
                    e.RightButton == MouseButtonState.Pressed &&
                    e.MiddleButton == MouseButtonState.Pressed &&
                    e.XButton1 == MouseButtonState.Pressed &&
                    e.XButton2 == MouseButtonState.Pressed);
            case MouseButtonState.Released:
                return (e.LeftButton == MouseButtonState.Released &&
                    e.RightButton == MouseButtonState.Released &&
                    e.MiddleButton == MouseButtonState.Released &&
                    e.XButton1 == MouseButtonState.Released &&
                    e.XButton2 == MouseButtonState.Released);
            default:
                return false;
        }
    }
}

(并不是所有人都会检查是否按下所有5个按钮..)

然后你可以这样检查:

if (mouseEventArgs.CheckUniformButtonState(MouseButtonState.Released))
{
    return;
}