用C#调用json

Question

我正在尝试使用C#进行json调用.我开始创建一个电话,但它不起作用:

public bool SendAnSMSMessage(string message)
{
    HttpWebRequest request = (HttpWebRequest)
                             WebRequest.Create("http://api.pennysms.com/jsonrpc");
    request.Method = "POST";
    request.ContentType = "application/json";

    string json = "{ \"method\": \"send\", "+
                  "  \"params\": [ "+
                  "             \"IPutAGuidHere\", "+
                  "             \"msg@MyCompany.com\", "+
                  "             \"MyTenDigitNumberWasHere\", "+
                  "             \""+message+"\" " +
                  "             ] "+
                  "}";

    StreamWriter writer = new StreamWriter(request.GetRequestStream());
    writer.Write(json);
    writer.Close();

    return true;
}

任何关于如何使这项工作的建议将不胜感激.

Answer 1

在您的代码中,您没有获得HttpResponse,因此您将看不到服务器端发回的内容.

你需要得到类似于你获得(制作)请求的方式.所以

public static bool SendAnSMSMessage(string message)
{
  var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://api.pennysms.com/jsonrpc");
  httpWebRequest.ContentType = "text/json";
  httpWebRequest.Method = "POST";

  using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
  {
    string json = "{ \"method\": \"send\", " +
                      "  \"params\": [ " +
                      "             \"IPutAGuidHere\", " +
                      "             \"msg@MyCompany.com\", " +
                      "             \"MyTenDigitNumberWasHere\", " +
                      "             \"" + message + "\" " +
                      "             ] " +
                      "}";

    streamWriter.Write(json);
  }
  var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
  using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
  {
    var responseText = streamReader.ReadToEnd();
    //Now you have your response.
    //or false depending on information in the response
    return true;        
  }
}

我还注意到在pennysms文档中他们期望内容类型为"text/json"而不是"application/json".这可能没有什么区别,但是如果它不起作用,它值得尝试.

Answer 2

继续@Mulki用他的代码做的事情

public string WebRequestinJson(string url, string postData)
{
    string ret = string.Empty;

    StreamWriter requestWriter;

    var webRequest = System.Net.WebRequest.Create(url) as HttpWebRequest;
    if (webRequest != null)
    {
        webRequest.Method = "POST";
        webRequest.ServicePoint.Expect100Continue = false;
        webRequest.Timeout = 20000;

        webRequest.ContentType = "application/json";
        //POST the data.
        using (requestWriter = new StreamWriter(webRequest.GetRequestStream()))
        {
            requestWriter.Write(postData);
        }
    }

    HttpWebResponse resp = (HttpWebResponse)webRequest.GetResponse();
    Stream resStream = resp.GetResponseStream();
    StreamReader reader = new StreamReader(resStream);
    ret = reader.ReadToEnd();

    return ret;
}

Answer 3

这是Shiv Kumar的回答,使用Newtonsoft.Json(又名Json.NET):

public static bool SendAnSMSMessage(string message)
{
    var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://api.pennysms.com/jsonrpc");
    httpWebRequest.ContentType = "text/json";
    httpWebRequest.Method = "POST";

    var serializer = new Newtonsoft.Json.JsonSerializer();
    using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
    {
        using (var tw = new Newtonsoft.Json.JsonTextWriter(streamWriter))
        {
             serializer.Serialize(tw, 
                 new {method= "send",
                      @params = new string[]{
                          "IPutAGuidHere", 
                          "msg@MyCompany.com",
                          "MyTenDigitNumberWasHere",
                          message
                      }});
        }
    }
    var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
    using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
    {
        var responseText = streamReader.ReadToEnd();
        //Now you have your response.
        //or false depending on information in the response
        return true;        
    }
}