Angular:如何在RouteGuard 中相对于目标路由调用router.navigate()?

Far*_*ruq 3 angular-routing angular angular-route-guards

我有一个使用 Angular 4 开发的现有项目。我需要根据用户权限控制对特定路由的访问。简化的路由配置如下所示:

[
    { path: '', redirectTo: '/myApp/home(secondary:xyz)', pathMatch: 'full' },
    { path: 'myApp'
      children: [
        { path: '', redirectTo: 'home', pathMatch: 'full' },
        { path: 'home', ... },
        ...
        { path: 'product'
          children: [
            { path: '', redirectTo: 'categoryA', pathMatch: 'full' },
            { path: 'categoryA', component: CategoryAComponent, canActivate: [CategoryACanActivateGuard]},
            { path: 'categoryB', component: CategoryBComponent},
            ...
          ]
        },
        ...
      ]
    },
    ...
]
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现在,我想控制对www.myWeb.com/myApp/product/categoryA. 如果用户没有足够的权限,他/她将被重定向到... /product/CategoryB。我已经写了一个CanActivateRouteGuard 来做到这一点,守卫类看起来像这样:

import { Injectable } from '@angular/core';
import { CanActivate, Router, ActivatedRouteSnapshot, RouterStateSnapshot, ActivatedRoute } from '@angular/router';
import { MyService } from '... my-service.service';

@Injectable()
export class CategoryACanActivateGuard implements CanActivate {
    constructor(private myService: MyService, private router: Router) { }

    canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): Promise<boolean> {
        return this.myService.checkPermission()
            .then(result => {
                if (!result.hasAccess) {
                    //redirect here

                    this.router.navigate(['./myApp/product/categoryB']); 
                    //works, but I want to remove hardcoding 'myApp'

                    //this.router.navigate(['../../categoryB']);
                    //doesn't work, redirects to home page

                    //this.router.navigate(['./categoryB'], { relativeTo: this.route});
                    //do not have this.route object. Injecting Activated route in the constructor did not solve the problem

                }
                return result.hasAccess;
            });
    }
}
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一切正常,但我想相对于目标路由重定向,如下所示:

this.router.navigate(['/product/categoryB'], { relativeTo: <route-of-categoryA>});
// or 
this.router.navigate(['/categoryB'], { relativeTo: <route-of-categoryA>});
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不幸的是,relativeTo只接受ActivatedRoute对象,而我所拥有的只是ActivatedRouteSnapshotand RouterStateSnapshot。有没有办法相对于目标路线导航(在这种情况下categoryA)?任何帮助将不胜感激。

笔记:

  • 除了添加一些路由保护之外,我无法更改路由配置。
  • 我不是在寻找this.router.navigateByUrl使用state.url. 我想用router.navigate([...], { relativeTo: this-is-what-need}).

Far*_*ruq 11

事实证明,与Component等其他地方相比ActivatedRouteRouteGuard 中注入的构造函数的工作方式有所不同。

在组件中,ActivatedRouteobject 指向激活该组件的路由。例如,在CategoryAComponent类中,以下代码将导航到CategoryB

this.router.navigate([ '../CategoryB' ], { relativeTo: this.route });
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但是,上面的相同代码在RouteGuard添加到CategoryA路由配置的类中不起作用。在我的测试中,我发现构造函数注入的ActivatedRoute对象指向根路由。另一方面,ActivatedRouteSnapshot对象(在canActivate函数中作为参数传入)指向目标路径(在我的例子中categoryA)。但是,我们不能ActivatedRouteSnapshotthis.router.navigate(...)函数中传递这个对象。

我找不到更好的方法来解决这个问题,但以下代码对我有用:

canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): Promise<boolean> {
    return this.myService.checkPermission()
        .then(result => {
            if (!result.hasAccess) {
                //redirect here

                let redirectTo = route.pathFromRoot
                    .filter(p => p !== route && p.url !== null && p.url.length > 0)
                    .reduce((arr, p) => arr.concat(p.url.map(u => u.path)), new Array<string>());

                this.router.navigate(redirectTo.concat('categoryB'), { relativeTo: this.route });
            }
            return result.hasAccess;
        });
}
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Chl*_*dog 9

我可以为您提供一个更精简的解决方案:

import {
  CanActivateFn,
  UrlTree,
  ActivatedRouteSnapshot,
  RouterStateSnapshot,
  createUrlTreeFromSnapshot
} from '@angular/router';
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const canActivate: CanActivateFn = (
  route: ActivatedRouteSnapshot,
  state: RouterStateSnapshot
): true | UrlTree {
  const urlTree = createUrlTreeFromSnapshot(route, ['categoryB']);
  return result.hasAccess || urlTree;
}
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通过这个解决方案,您可以非常轻松地设置您可能需要的所有其他道具 - 命名插座导航、查询参数、片段......

从快照创建UrlTree


小智 5

您可以使用 Angular 14 中的新createUrlTreeFromSnapshot()函数,如下所示:

const urlTree = createUrlTreeFromSnapshot(routeSnapshot, ['../categoryB']);
this.router.navigateByUrl(urlTree);
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