在Python Pandas中查找两列的交集 - >字符串列表

Question

我想计算A列和B列相交的实例数.A列和B列中的行是字符串列表.例如,列A可以包含[汽车,乘客,卡车],列B可以包含[汽车,房屋,花卉,卡车].由于在这种情况下,2个字符串重叠,列C应显示 - > 2

我试过了(这些都没有):

df['unique'] = np.unique(frame[['colA', 'colB']])

要么

def unique(colA, colB):
    unique1 = list(set(colA) & set(colB))
    return unique1

df['unique'] = df.apply(unique, args=(df['colA'], frame['colB']))

TypeError :('unique()需要2个位置参数,但3个被赋予','发生在索引文章')

Answer 1

我认为需要length有set.intersection在列表理解:

df['C'] = [len(set(a).intersection(b)) for a, b in zip(df.A, df.B)]

要么:

df['C'] = [len(set(a) & set(b)) for a, b in zip(df.A, df.B)]

样品:

df = pd.DataFrame(data={'A':[['car', 'passenger', 'truck'], ['car', 'truck']],
                        'B':[['car', 'house', 'flower', 'truck'], ['car', 'house']]})
print (df)
                         A                            B
0  [car, passenger, truck]  [car, house, flower, truck]
1             [car, truck]                 [car, house]

df['C'] = [len(set(a).intersection(b)) for a, b in zip(df.A, df.B)]
print (df)
                         A                            B  C
0  [car, passenger, truck]  [car, house, flower, truck]  2
1             [car, truck]                 [car, house]  1