findViewById(int)方法未定义

Question

我是Android开发的新手,我正在尝试编写一个小应用程序,它允许我获取外部JSON文件并解析它.我得到了它的工作,但如果我尝试在后台执行它作为一个它不会工作AsyncTask.Eclipse给了我错误

对于LongOperation类型,方法findViewById(int)未定义

在这一行:

TextView txtView1 =(TextView)findViewById(R.id.TextView01);

这是我的代码:

public class Main extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        new LongOperation().execute();
    }
}


class LongOperation extends AsyncTask<String, Void, String> {
    private final Context LongOperation = null;


    @Override
    protected String doInBackground(String... params) {
        try {
            URL json = new URL("http://www.corps-marchia.de/jsontest.php");
            URLConnection tc = json.openConnection();
            BufferedReader in = new BufferedReader(new InputStreamReader(tc.getInputStream()));

            String line;
            while ((line = in.readLine()) != null) {
                    JSONArray ja = new JSONArray(line);
                    JSONObject jo = (JSONObject) ja.get(0);
                    TextView txtView1 = (TextView)findViewById(R.id.TextView01);
                    txtView1.setText(jo.getString("text") + " - " + jo.getString("secondtest"));
            }
        } catch (MalformedURLException e) {
            Toast.makeText(this.LongOperation, "Malformed URL Exception: " + e, Toast.LENGTH_LONG).show();
        } catch (IOException e) {
            Toast.makeText(this.LongOperation, "IO Exception: " + e, Toast.LENGTH_LONG).show();
        } catch (JSONException e) {
            Toast.makeText(this.LongOperation, "JSON Exception: " + e, Toast.LENGTH_LONG).show();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String result) {
    }
    protected void onPreExecute() {
    }

    @Override
    protected void onProgressUpdate(Void... values) {
        ProgressDialog pd = new ProgressDialog(LongOperation);
        pd.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL);
        pd.setMessage("Working...");
        pd.setIndeterminate(true);
        pd.setCancelable(false);
    }    

}

有想法该怎么解决这个吗？

Answer 1

这是你应该做的,使它按你想要的方式工作.使用onPostExecude()

public class Main extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        new LongOperation(this).execute();
    }
}


class LongOperation extends AsyncTask<String, Void, String> {
    private Main longOperationContext = null;

    public LongOperation(Main context) {
        longOperationContext = context;
        Log.v("LongOper", "Konstuktor");
    }

    @Override
    protected String doInBackground(String... params) {
        Log.v("doInBackground", "inside");
        StringBuilder sb = new StringBuilder();

        try {
            URL json = new URL("http://www.corps-marchia.de/jsontest.php");
            URLConnection tc = json.openConnection();
            BufferedReader in = new BufferedReader(new InputStreamReader(tc.getInputStream()));

            String line;
            while ((line = in.readLine()) != null) {
                    JSONArray ja = new JSONArray(line);
                    JSONObject jo = (JSONObject) ja.get(0);
                    Log.v("line = ", "jo.getString() ="+jo.getString("text"));
                    sb.append(jo.getString("text") + " - " + jo.getString("secondtest")).append("\n");
            }
        } catch (MalformedURLException e) {
            e.printStackTrace();
            Log.v("Error", "URL exc");
        } catch (IOException e) {
            e.printStackTrace();
            Log.v("ERROR", "IOEXECPTOIn");
        } catch (JSONException e) {
            e.printStackTrace();
            Log.v("Error", "JsonException");
        }
        String result = sb.toString();
        return result;
    }

    @Override
    protected void onPostExecute(String result) {
        Log.v("onPostExe", "result = "+result);
      TextView txtView1 = (TextView)longOperationContext.findViewById(R.id.textView01);
      txtView1.setText(result);


    }
    protected void onPreExecute() {
    }

    @Override
    protected void onProgressUpdate(Void... values) {
        ProgressDialog pd = new ProgressDialog(longOperationContext);
        pd.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL);
        pd.setMessage("Working...");
        pd.setIndeterminate(true);
        pd.setCancelable(false);
    }    

}

Answer 2

AsyncTask其他答案之一的实施是有缺陷的。每次在 内都会创建进度对话框publishProgress，并且对对话框的引用在方法外部不可见。这是我的尝试：

public class Main extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        new LongOperation().execute();
    }
    class LongOperation extends AsyncTask<String, Void, String> {
        ProgressDialog pd = null;
        TextView tv = null;

        @Override
        protected void onPreExecute(){
            tv = Main.this.findViewById(R.id.textvewid);
            pd = new ProgressDialog(Main.this);
            pd.setMessage("Working...");
            // setup rest of progress dialog
        }
        @Override
        protected String doInBackground(String... params) {
            //perform existing background task
            return result;
        }
        @Override
        protected void onPostExecute(String result){
            pd.dismiss();
            tv.setText(result);
        }
    }
}