使用Wicket AbstractAjaxBehavior和jQuery.ajax()

Question

我已经使用jQuery AJax调用来发送JSON,如StackOverflow中所述

问题是我没有收到服务器上的任何数据.我可以看到调用确实达到了目标ajax行为 - 但在onRequest()方法中,RequestCycle dd不包含任何参数

我的Wicket代码:

        AbstractAjaxBehavior ajaxSaveBehaviour = new AbstractAjaxBehavior(){
        private static final long serialVersionUID = 1L;

        @SuppressWarnings("unchecked")
        public void onRequest()
        {
            //get parameters
            final RequestCycle requestCycle = RequestCycle.get();



            final PageParameters pageParameters = new PageParameters(requestCycle.getRequest().getParameterMap());
            logger.info(" I have received something 1");

            for(String pkey: requestCycle.getRequest().getParameterMap().keySet()){
                String[] valArry= requestCycle.getRequest().getParameterMap().get(pkey);
                StringBuffer sb = new StringBuffer();
                for(String s: valArry) sb.append(s).append(" , ");
                logger.info("pk :"+ pkey + " = "+ sb.toString());
            }

            //do something using nice json library to produce a string of json

            logger.info(" I have received something 2");
            for(String key: pageParameters.keySet()){
                Object o= pageParameters.get(key);
                logger.info("received key : "+ key + "   = " +o.toString());                    
            }





            String data="ok";        

            requestCycle.setRequestTarget(new StringRequestTarget("application/json", "utf-8", data));
        }


    };
    add(ajaxSaveBehaviour);
    String callBackURL= ajaxSaveBehaviour.getCallbackUrl().toString();

我的Javascript调用此方法

console.log(" call back url :"+ callBackURL);
           $.ajax({
                url: callBackURL,
                type: 'post',
                cache: false,

                data:JSON.stringify(ccbArry[0]),
                contentType: 'application/json',
                dataType: 'json',
                complete: function() {
                        alert(" completed okey dokey!")
                }

            });

从我的Firebug控制台,我可以看到JSON POST成功完成并且警报("完成了okey dokey!")dos被触发.

问题是在Wicket上,AbstractAjaxBehavior无法在RequestCycle中找到任何参数.

有什么我想念的吗？有趣的是,我运行这是调试器,因为我找不到任何参数.这看起来像编码问题.

从Firebug,我可以看到这是发出的电话

http://localhost:8080/mywebapp-web-1.0-SNAPSHOT/?wicket:interface=:0::IActivePageBehaviorListener:0:&wicket:ignoreIfNotActive=true&%7B%22type%22%3A9504%2C%22sourceNewsClipBean%22%3A%7B%22type%22%3A9503%2C%22id%22%3A%224cf05752acc1d6aebface86d%22%2C%22typeString%22%3A%22NEWSCLIP_TYPE%22%7D%2C%22startOffset%22%3A%22195%22%2C%22clipDuration%22%3A%22297%22%7D=

不知何故,这些参数在RequestCycle中没有出现.它看起来像一个狡猾的问题.有任何想法吗 ？

Answer 1

好吧,我找到了解决方案:关键是不使用requestCycle.getRequest().getParameterMap()从浏览器中读取JSON.而是直接从servlet输入流中读取数据,如下所示:它可以工作.

            public void onRequest()
        {
            //get parameters
            final RequestCycle requestCycle = RequestCycle.get();


            WebRequest wr=(WebRequest)requestCycle.getRequest();

            HttpServletRequest hsr= wr.getHttpServletRequest() ;

            try {
                BufferedReader br = hsr.getReader();

                       String  jsonString = br.readLine();
                       if((jsonString==null) || jsonString.isEmpty()){
                           logger.error(" no json found");
                       }
                       else {
                           logger.info(" json  is :"+ jsonString);
                       }



            } catch (IOException ex) {
                logger.error(ex);
            }


            // json string to retir to the jQuery onSuccess function
            String data=getReturnJSONValue();

            logger.info("returning json :"+ data);
            IRequestTarget t = new StringRequestTarget("application/json", "UTF-8", data);
            getRequestCycle().setRequestTarget(t);


            //requestCycle.setRequestTarget(new StringRequestTarget("application/json", "utf-8", data));
        }