Swift4 JSONDecoder预计解码Dictionary <String,Any>但是找到了一个数组

A B*_*uit 8 php json swift

我对此很新手,但我一直试图弄清楚JSONDecoder如何为需要从MySQL数据库检索数据的登录功能起作用,如下面的代码所示,并且收到此错误.

SWIFT代码:

func testParseJson(){

                var request = URLRequest(url: URL(string: "https://test.php")!)
        request.httpMethod = "POST"

        let postString = ("Email=test&Password=test")
        print(postString)
        request.httpBody = postString.data(using: .utf8)

        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data else { return }
            do {
                var responseString = String(data: data, encoding: .utf8)!
                print("new response string \(responseString)")
                let decoder = JSONDecoder()
                let newData = try decoder.decode(User.self, from: data)
                print(newData.Email)
                print(newData.UserType)
            } catch let err {
                print("Err", err)
            }
            }.resume()
    }
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临时结构我一直试图使用:

struct User: Decodable {
 let U_ID: String
 let Email: String
 let Password: String
 let UserType: String

private enum CodingKeys: String, CodingKey {
    case U_ID
    case Email
    case Password
    case UserType
 }
}
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JSON响应字符串如下:

[{"U_ID":"1",
"Email":"test",
"Password":"test",
"UserType":"Teacher"}]
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任何帮助都将受到大力赞赏.

Raj*_*n S 24

在这里,JSON数据ArrayObjects.

更改

try decoder.decode(User.self, from: data)
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try decoder.decode(Array<User>.self, from: data)
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例:

var users = [User]()

let data = """
[{"U_ID":"1","Email":"test","Password":"test","UserType":"Teacher"}]
""".data(using: .utf8)

do{
    users = try JSONDecoder().decode(Array<User>.self, from: data!)
}catch{
    print(error.localizedDescription)
}

print(users.first?.Email)
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注意:为了更好地理解,这是我在swift 4中关于JSON解析的视频系列

  • 那效果很好。作为另一个菜鸟问题,因为我对 swift 很陌生,我如何从应用程序中的其他地方访问 users.first?.Email?它是一个登录名,但稍后需要再次使用该电子邮件。非常感谢 (2认同)