当标准输入是管道时如何从设备读取

jap*_*jap 4 stdin pipe go

所以我有一个从 STDIN 读取的 Go 程序,如下所示。我希望从键盘或设备输入用户名和密码,但可以使用管道传递字符串切片。如果我运行如下命令:

echo "Hello World" | go run main.go
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os.Stdin将被设置为从管道读取,而不是从键盘读取。有没有一种方法可以更改os.StdinFileMode,使其从设备(即键盘)读取用户名和密码?

我尝试使用os.Stdin.Chmod(FileMode)但收到此错误:

chmod /dev/stdin:参数无效

func main() {
  var n = []string{}
  scanner := bufio.NewScanner(os.Stdin)
  fmt.Println("Please type anything with Newline Separated, empty line signals termination")
  for scanner.Scan() {
    h := scanner.Text()
    if h == "" {
      break
    }
    n = append(n, h)
  }
  if err := scanner.Err(); err != nil {
    fmt.Printf("Error in reading from STDIN: %v\n", err)
  }

  reader := bufio.NewReader(os.Stdin)
    os.Stdout.WriteString("Username: ")
    username, err := reader.ReadString('\n')
    if err != nil {
        fmt.Printf("Unable to read username: %v\n", err)
  }
  username = strings.TrimSpace(username)

  os.Stdout.WriteString("Password: ")
  bytePassword, _ := terminal.ReadPassword(int(os.Stdin.Fd()))

  password := string(bytePassword)
  os.Stdout.WriteString("\n")
}
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nba*_*ari 6

也许scanf可以提供帮助,请检查这个示例:

https://play.golang.org/p/tteQNl0trJp

package main

import (
    "fmt"
)

func main() {
    fmt.Println("Enter your name")

    var name string
    fmt.Scanf("%s", &name)
    fmt.Printf("name = %s\n", name)
}
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更详细的内容是检查是否有东西可以从标准输入读取,如果没有提示用户:

https://play.golang.org/p/7qeAQ5UNhdQ

package main

import (
    "bufio"
    "fmt"
    "log"
    "os"
)

func main() {
    // check if there is somethinig to read on STDIN
    stat, _ := os.Stdin.Stat()
    if (stat.Mode() & os.ModeCharDevice) == 0 {
        var stdin []byte
        scanner := bufio.NewScanner(os.Stdin)
        for scanner.Scan() {
            stdin = append(stdin, scanner.Bytes()...)
        }
        if err := scanner.Err(); err != nil {
            log.Fatal(err)
        }
        fmt.Printf("stdin = %s\n", stdin)
    } else {
        fmt.Println("Enter your name")

        var name string
        fmt.Scanf("%s", &name)
        fmt.Printf("name = %s\n", name)
    }
}
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