如何在tableview单元格中传递字典?

Far*_*azi -1 dictionary uitableview swift

import UIKit

class ViewController: UIViewController, UITableViewDataSource,UITableViewDelegate {

    @IBOutlet weak var label: UILabel!
    @IBOutlet weak var imageView: UIImageView!
    @IBOutlet weak var tableView1: UITableView!

    let element = ["Sports": #imageLiteral(resourceName: "ios"),"Grocery":#imageLiteral(resourceName: "ios"),"Cosmetics":#imageLiteral(resourceName: "ios")]

    override func viewDidLoad() {
        super.viewDidLoad()
        tableView1.delegate = self
        tableView1.dataSource = self
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return element.count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) ->UITableViewCell{
        let cell = tableView1.dequeueReusableCell(withIdentifier: "customcell",for: indexPath)

        cell.textLabel?.text = element.keys

        cell.imageView?.image = element.values
        return cell
    }

}
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嘿伙计们,我怎么能在同一个单元格中显示字典键和值.

Ros*_*han 5

将类型添加到数组[String: UIImage]和类型转换,element.keys并将数组添加到element.values:

Array(element.keys)Array(element.values)

如果您没有进行类型转换element.keyselement.values数组,那么您将收到类似的错误Cannot subscript a value of type 'Dictionary<String, UIImage>.Keys' with an index of type 'Int

let element: [String: UIImage] = ["Sports": #imageLiteral(resourceName: "ios"),"Grocery":#imageLiteral(resourceName: "ios"),"Cosmetics":#imageLiteral(resourceName: "ios")]

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) ->UITableViewCell{
    let cell = tableView.dequeueReusableCell(withIdentifier: "customcell",for: indexPath)
    cell.textLabel?.text = Array(element.keys)[indexPath.row]
    cell.imageView?.image = Array(element.values)[indexPath.row]
    return cell
}
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